Answer:
multiply the left side of the constant vector by the inverse matrix
Step-by-step explanation:
The matrix equation ...
AX = B
is solved by left-multiplying by the inverse of A:
A⁻¹AX = A⁻¹B
IX = A⁻¹B . . . . . the result of multiplying A⁻¹A is the identity matrix
X = A⁻¹B . . . . . B needs to be multiplied by the inverse matrix
![\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}-4&1\\3&2\end{array}\right]^{-1}\left[\begin{array}{c}9&7\end{array}\right]=\dfrac{1}{11}\left[\begin{array}{cc}-2&1\\3&4\end{array}\right]\left[\begin{array}{c}9&7\end{array}\right]=\left[\begin{array}{c}-1&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%26y%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-4%261%5C%5C3%262%5Cend%7Barray%7D%5Cright%5D%5E%7B-1%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%267%5Cend%7Barray%7D%5Cright%5D%3D%5Cdfrac%7B1%7D%7B11%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-2%261%5C%5C3%264%5Cend%7Barray%7D%5Cright%5D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D9%267%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-1%265%5Cend%7Barray%7D%5Cright%5D)
Answer:
6/3 as an Improper Fraction.
2 as a whole number.
Step-by-step explanation:
2/3 multiplied by 3 is as shown below.
2/3 + 2/3 + 2/3.
As an Improper Fraction, the sum would be expressed as:
2 + 2 + 2 = 6. 6/3
2/3 • 3 = 2, since 6/3 = 2 as well.
Answer:
(3/2, -1/2)
Step-by-step explanation:
add the 2 inequalities together.
you get 2X<3 so x<3/2. plug X back in and solve for y and you get y= -1/2
F(x) = x + 1
------
b
g(x) = cx - d
flip values of x and y in each equation, then solve for y:
x = y + a
-------
b
y = a - bx
``````````````````````````````````````````````````````````
x = cy - d
y = x + d
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c
I know b is James, Olivia, Feng, Carmela
