Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
Answer:
$2,400
Step-by-step explanation:
Ken intends to start a savings account
10% = leisure spending
This means 90% = Expenses for school
Let us represent the amount he must save as : x
Hence in other for him to have $2,160 in his savings account, the amount Ken must earn is calculated as:
90/100 × x = $2,160
Cross Multiply
90x = $2,160 × 100
x = ($2,160 × 100) ÷ 90
x =$2,400
Therefore, the amount Ken has to earn to have the amount needed for school is $2,400
Answer:
17/13
Step-by-step explanation:
r(6) = 3(6) - 1 = 17 and s(6) = 2(6) + 1 = 13.
Then (r/s)(6) = 17/13.
Answer:
$44.45
Step-by-step explanation:
Convert 15 2/5% to decimal, =0.154
38.52+(38.52x0.154) (do this to add the cost of the % increase)
≈$44.45.
