Answer:
I elieve the answer for this is Juniper Network Firewall
Hope this helps
<span>Make eye contact look at everyone ur speaking to not just one person speak loud and clearly make sure your understandable</span>
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
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It basically comes down to what programming language you want to learn.
Answer:
false
Explanation:
A reference parameter passed into the method can be changed by the method, when the method changes all of a parameter's variables, the parameter will keep the changes after the method is returned.