Answer:
D. return str.substring(0, 1) + removeDupChars(str.substring(1));
Explanation:
The logic here is following:
If the there are consecutive duplicate characters, return the removeDupChars method. The parameter of the removeDupChars method is a string, but the duplicate of the first character is removed from the string. The else-if part of the program does this job.
If the consecutive characters are not duplicated, return the first character of the string and the removeDupChars method. The parameter of the removeDupChars method is the rest of the string characters. The else part of the program does this job.
When the length of the str becomes one (or when the str is null), the program reaches its base and returns the str. The if part of the program does this job.
Answer:
def countdown(n):
if n <= 0:
print('Blastoff!')
else:
print(n)
countdown(n-1)
def countup(n):
if n >= 0:
print('Blastoff!')
else:
print(n)
countup(n+1)
number = int(input("Enter a number: "))
if number >= 0:
countdown(number)
elif number < 0:
countup(number)
<u>Outputs:</u>
Enter a number: 3
3
2
1
Blastoff!
Enter a number: -3
-3
-2
-1
Blastoff!
Enter a number: 0
Blastoff!
For the input of zero, the countdown function is called.
Explanation:
Copy the countdown function
Create a function called countup that takes one parameter, n. The function counts up from n to 0. It will print the numbers from n to -1 and when it reaches 0, it will print "Blastoff!".
Ask the user to enter a number
Check if the number is greater than or equal to 0. If it is, call the countdown function. Otherwise, call the countup function.
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