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kati45 [8]
3 years ago
8

2x+y=3-x + 3y = -12​

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0
Use Photomath it’s amazing
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Two factors of –48 have a difference of 19. The factor with a greater absolute value is positive. What is the sum of the factors
statuscvo [17]

Answer:

13

Step-by-step explanation:

Two factors of -48... that means two numbers which multiplied together give a result of -48, like -6 and 8 for example.

The difference of those two factors is -19.  There not that many possible factors for -48, so if we list them we'll be able to spot a pair with a difference of 19.

A first list of factors for -48 is: -1 and 48, -2 and 24, -3 and 16, -4 and 12, -6 and 8.

We can create another list by inverting the signs: 1 and -48, 2 and -24, 3 and -16, 4 and -12, 6 and -8.

The question says the difference of the two factors is 19...  can you spot in each list a pair of factors having a difference of 19?   I see -3 and 16 and also 3 and -16.

The question also say the one of the greatest absolute value is positive... so that  means it's a pair with +16, not -16.

The pair of factors we're looking for is then -3 and 16. They are factors of -18, they have a difference of 19, and the one with the greatest absolute value is positive.

The sum of -3 and 16 is 13.

7 0
4 years ago
The circumcenter of AMNP, find each measure <br> A=<br> NE=<br> MD=
Oksana_A [137]
60% 30% 160% that’s for each one in order
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3 years ago
Question 6 look at pic pls​
pentagon [3]

Answer:

i would pick option c

because i wrote the question down and answered it your welcome

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4 years ago
9 gallons at $1.92 per gallon
stira [4]
1.92*9=17.28

The total would be $17.28
8 0
3 years ago
Read 2 more answers
Find a degree 3 polynomial having zeros -5, 1 and 5 and the coefficient of x^3 equal 1
mote1985 [20]

Answer:

x^3 -x^2 -25x +25

Step-by-step explanation:

\text{The roots are,}~ \alpha  = -5,~ \beta = 1 ~ \text{and}~ \gamma = 5\\\\\text{The polynomial is,}\\\\~~~x^3 - (\alpha + \beta + \gamma)x^2+(\alpha \beta + \beta \gamma+ \gamma \alpha)x - \alpha\beta \gamma\\\\=x^3 - (-5+1+5)x^2 +(-5 \cdot 1 + 1 \cdot 5 + 5 \cdot -5)x - (-5)(1)(5)\\\\=x^3 -(0+1)x^2 + (-5+5-25)x +25\\\\=x^3 -x^2 -25x +25

7 0
2 years ago
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