Answer:
x=15
Step-by-step explanation:
This is a simultaneous equation
2x-3y=45 ------------------------------ equation i
x+y=10 -------------------------------equation ii
from equation ii
x+y=10
make x the subject of the matter
we have,
x=10-y
in equation i
substitute x for 10-y
2x-3y=45----------------------i
since x=10-y
we have,
2(10-y) - 3y=45
20-2y=3y=45
collect like terms
-2y-3y=45-20
-5y=25
divide both sides by -5
we have y=-5
substitute y for-5 in equation i
x+y=10
x+-5=10
collect like terms
x=10+5
x=15
therefore
x=15
Answer:
Shift 2 unit left
Flip the graph about y-axis
Stretch horizontally by factor 2
Shift vertically up by 2 units
Step-by-step explanation:
Given:
Parent function: 
Transformation function: 
Take -2 common from transform function f(x)
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Now we see the step-by-step translation

Shift 2 unit left ( x → x+2 )

Flip the graph about y-axis ( (x+2) → - (x+2) )
![f(x)=\log[-(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-%28x%2B2%29%5D)
Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]
![f(x)=\log[-2(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D)
Shift vertically up by 2 units [ f(x) → f(x) + 2 ]
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Simplify the function:

Hence, Using four step of transformation to get new function 
In order for two lines to be perpendicular, their gradients must multiply together to get -1
7*b=-1
7b=-1
Divide both sides by 7
So, the gradient of line b is -1/7
Can you plz add a picture to show
Answer:11,17,24
Step-by-step explanation:
Lowest number=11
Range=13
Median=17
Range=highiest number - lowest number
13=highiest number -11
Highest number =13+11
Highest number=24
Ali's three numbers are 11,17,24