The least number of acute angles that a triangle can have is 2.
Let imagine you had 1 acute angle and 2 other angles that were non-acute (90° or higher)
a less than 90°
b less than 90°
c less than 90°
All the angles in a triangle add up to 180° (i.e) a + b + c = 180°
Since b and c are 90° or higher, that requires a to be negative. But we cannot have a negative angle, so there is no way to create a triangle with 1 (or fewer) acute angles.
<h3>Answer: <em><u>I </u></em><em><u>think</u></em><em><u> </u></em><em><u>letter </u></em><em><u>B </u></em></h3>
<h3>Explanation: <em><u>I </u></em><em><u>am </u></em><em><u>not </u></em><em><u>sure </u></em><em><u>to </u></em><em><u>me </u></em><em><u>answer </u></em><em><u>and </u></em><em><u>I </u></em><em><u>no </u></em><em><u>my </u></em><em><u>answer </u></em><em><u>is </u></em><em><u>correct</u></em></h3>
Answer:
Step-by-step explanation:
GIVEN: In the school year in country A, there were foreign students from country B. This number is more than the number of students from country C.
TO FIND: How many foreign students were from country C.
SOLUTION:
Total foreign students from country B
let the foreign students from country C be
As the students from country B is more than the country C
Students from country B
Hence the number of students from country C are
1, 2, 4, 8, 16
Hope this helps
Answer:
23.51
Step-by-step explanation: