There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
A=1 b=8 c=8
h = [-8 +-sq root(64 - 4*1*8)] / 2
h = [-8 +-sq root(32)] / 2
h1 = -4 +
<span>
<span>
<span>
2.8284271247
</span>
</span>
</span>
h1 =
<span>
<span>
<span>
-1.1715728753
</span>
</span>
</span>
h2 = -4 -
<span>
<span>
2.8284271247
</span></span>h2 = -<span> 6.8284271247
</span>
Answer:
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Step-by-step explanation:
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