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2 years ago

Please help me !!!!!!!!

Mathematics

1 answer:

LuckyWell [14K]2 years ago

7 0

51.3 I think you just have to subtract 68.5 to 17.2

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A firm makes bulldozers (B), cranes (C) and tractors (T) at two locations, New York City (NYC) and Los Angeles (LA). The matrice

iragen [17]

Answer:

The expression is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]$

Step-by-step explanation:

From the question we are told that

The number of each items made in the month of January[J] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{144}&{474 }&{274}\\{598}&{572}&{302}\\\end{array}\right]$

The number of each items made in the month of February[F] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ C \ \ \ \ \ \ T\\J = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{ 424}&{492}&{546}\\{596 }&{530}&{164}\\\end{array}\right]$

Generally given that the production for March of all products at all locations was the average of the January and February production then the number of each items made in the month of March[M] is

$.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ \ \ \ \ \ \ \ C \ \ \ \ \ \ \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{\frac{144 +424}{2}}&{\frac{474 +492}{2}}&{\frac{274 +546}{2}}\\{\frac{598 +596}{2}}&{\frac{572 +530}{2}}&{\frac{302+164}{2}}\\\end{array}\right]$

=> $.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ B \ \ \ \ \ \ C \ \ \ \ \ T\\M = \left \ NYC} \atop {LA}} \right. \left[\begin{array}{ccc}{284}&{483}&{410}\\{597}&{551}&{233}{2}}\\\end{array}\right]$

5 0

3 years ago

Eva is arranging 24 photos in an album. How many different ways can she arrange the photos so that the number of photos on each

mart [117]

1 x 24
2 x 12
3x8
4x6

Four different ways. Think of the factors of 24. Hint- only use the same number once!

6 0

3 years ago

How is 0.6 greater than 0.25 explain please.

Nutka1998 [239]

Oh I think is because when u write or draw a number line u write like 1,2,3,4,5 ... and -1,-2,-3... and so when u write point something....and so u have 0.6 and 0.25 and 0.6 is greater because it came first 0.6 came before 0.25

8 0

3 years ago

Can you guys please help me? I don't really get what it is asking us to do.

aleksandr82 [10.1K]

The correct answer is 160

And u have to do the question correctly...

Cuz I told u the answer......

Hope this helps......

8 0

3 years ago

A statistician calculates that 8% of Americans own a Rolls Royce. If the statistician is right, what is the probability that the

hichkok12 [17]

Answer:

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

A statistician calculates that 8% of Americans own a Rolls Royce.

This means that $p = 0.08$

Sample of 595:

This means that $n = 595$

Mean and standard deviation:

$\mu = p = 0.08$

$s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.08*0.92}{595}} = 0.0111$

What is the probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%?

Proportion above 8% + 3% = 11% or below 8% - 3% = 5%. Since the normal distribution is symmetric, these probabilities are equal, and so we find one of them and multiply by 2.

Probability the proportion is less than 5%:

P-value of Z when X = 0.05. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.05 - 0.08}{0.0111}$

$Z = -2.7$

$Z = -2.7$ has a p-value of 0.0035

2*0.0035 = 0.0070

0.007 = 0.7% probability that the proportion of Rolls Royce owners in a sample of 595 Americans would differ from the population proportion by more than 3%

8 0

3 years ago