Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
(x-1)(x-2)(x-3)
Step-by-step explanation:
hy vọng nó giúp
The distance is approximately 703 kilometers.
To travel that in 12 hours, a car has to go at 703/12=58.583 km/h
if you want all of problem here ^^^^^^^
Answer:
-6x
hope it's helpful ❤❤❤❤❤❤
THANK YOU.
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Sides are always equal. Pretty sure