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3 years ago

Which one is correct?

Mathematics

1 answer:

kupik [55]3 years ago

5 0

Answer:

Step-by-step explanation:

Subtract 1 from both sides and divide by 2. This will leave you with x=-2 which is the simplified form of the equation.

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Expand<br> c(3c - 3)<br> I need help on this

Rudik [331]

$\\ \sf\longmapsto c(3c-3)$

Apply distributive law

a(b-d)=ab-ad

$\\ \sf\longmapsto 3c(c)-3(c)$

$\\ \sf\longmapsto 3c^2-3c$

We can still take common

$\\ \sf\longmapsto 3c(c-1)$

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2 years ago

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What is another way to show that 4/6 = 8/12?

Varvara68 [4.7K]

what I think is the answer is 2/3

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3 years ago

Which statements are true about the curve? Check all

Shalnov [3]

Answer

The answer is 2,3,5

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3 years ago

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butalik [34]

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3 years ago

Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr

Degger [83]

Answer:

$A=73.8\°$

$B=8.2\°$

$c=76.3\ units$

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

$c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)$

substitute the given values

$c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)$

$c^{2}=5,823.5738$

$c=76.3\ units$

step 2

Find the measure of angle A

Applying the law of sine

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}$

$sin(A)=(74)sin(98\°)/76.3$

$A=arcsin((74)sin(98\°)/76.3)$

$A=73.8\°$

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

$A+B+C=180\°$

substitute the given values

$73.8\°+B+98\°=180\°$

$171.8\°+B=180\°$

$B=180\°-171.8\°=8.2\°$

5 0

3 years ago