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mafiozo [28]
2 years ago
14

2. Write the following number in standard form: (3.NSBT.4)

Mathematics
1 answer:
irina1246 [14]2 years ago
4 0
The answer is: 384,022
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ANSWER PLEASSSSSSSSSSSE
kolezko [41]

Answer:

The answer is A hope this helps

Step-by-step explanation:

3x^2+14x+16=0

(3x+8)(x+2)=0

x=-8/3 or -2

7 0
3 years ago
Yasmin uses 4 cups of papaya juice for every 6 cups of pineapple juice. If Yasmi already has 24 cups of pineapple juice, how man
lilavasa [31]

Answer:

Step-by-step explanation:

The ratio is 4:6 4 papaya to 6 pineapple

This turns out to be for every 1 cup of papaya juice you have 1.5 cups of pineapple juice.

If you have 24 cups of pineapple juice divide 24 by 1.5 to get 16 cups of papaya juice. 16:24.

6 0
2 years ago
Write yhr equation in standard form of the line with m=3/4 and b=6
ozzi

Answer:

y = 3/4 x + 6

Step-by-step explanation:

y = mx + b

y = 3/4 x + 6

3 0
3 years ago
Can someone help me figure this out no guessing
laiz [17]
Your answer is x = 2.92 = 3.
To answer this question you need to use trigonometry, so the first step is to identify the hypotenuse, opposite, and adjacent.
Because the angle 73 is in the bottom corner next to the length x, we know that the length x is the adjacent. The length 10 is opposite the right angle so this must be the hypotenuse.
We know that cos(θ) = adjacent/hypotenuse, so we can substitute in what we know:
cos(θ) = adjacent/hypotenuse
cos(73) = x/10
Now we can rearrange for x:
cos(73) = x/10
× 10
cos(73) × 10 = x
Finally we just type this into the calculator and get the answer as 2.92 or 3.
I hope this helps!
5 0
2 years ago
2sin^2 2x=2<br><br> In the domain [0,2pi)<br><br> What can x equal ( in radians).
lions [1.4K]
Bear in mind that, when it comes to trigonometric functions, the location of the exponent can be a bit misleading, however recall that sin²(θ) is really [ sin( θ )]²,


\bf 2sin^2(2x)=2\implies sin^2(2x)=\cfrac{2}{2}&#10;\\\\\\&#10;sin^2(2x)=1\implies [sin(2x)]^2=1\implies sin(2x)=\pm\sqrt{1}&#10;\\\\\\&#10;sin(2x)=\pm 1\implies sin^{-1}[sin(2x)]=sin^{-1}(\pm 1)

\bf \measuredangle 2x=sin^{-1}(\pm 1)\implies \measuredangle 2x=&#10;\begin{cases}&#10;\frac{\pi }{2}\\\\&#10;\frac{3\pi }{2}&#10;\end{cases}\\\\&#10;-------------------------------\\\\&#10;\measuredangle 2x=\cfrac{\pi }{2}\implies \measuredangle x=\cfrac{\pi }{4}\qquad \qquad \qquad \qquad \measuredangle 2x=\cfrac{3\pi }{2}\implies \measuredangle x=\cfrac{3\pi }{4}
3 0
3 years ago
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