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rusak2 [61]
2 years ago
5

A stack of magazines is 4 2/5 inches high. Each magazine is 2/5 inch thick.

Mathematics
1 answer:
oee [108]2 years ago
7 0

Answer:

Equation:(4 2/5)/2/5=? ; estimate: a

little more than 10 magazines; answer:

11 magazines in the stack.

Step-by-step explanation:

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Which statement is logically equivalent to the following conditional statement?
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Hi there! Your answer would be:

D, If it is an octagon, then it does not have exactly five sides.

I also know because I took this exam and it was correct.


Hope that helps!

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1 year ago
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What is the least common multiple of15&25
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The LCM of 15 and 25 is 75.
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Can someone explain to me how to find mean/median of a data set real quick?
PIT_PIT [208]
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3 years ago
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A parallelogram has sides of 18 and 26 ft, and an angle of 39° . Find the shorter diagonal
Fed [463]

Answer:

16.51

Step-by-step explanation:

In a parallelogram, the opposite angles are always equal in measure. So two of the angles in the parallelogram measure 39 degrees each.

The sum of angles of the parallelogram must be 360 degrees. Let the other two angles be x degree each. We can set up the following equation for the angles:

39 + 39 + x + x = 360

78 + 2x = 360

2x = 282

x = 141

This means, the other two angles measure 141 degree each. The shorter diagonal will be opposite to the shorter angle.

Hence, the diagonal opposite to the angle 39 degree will be the shorter one. A diagonal divides the parallelogram in two triangles. So we will have two sides and an included angle and we have to find the third side of the triangle which can be found using the law of cosines. Let the third side be c as shown in image below, using the law of cosines, we can write:

c^{2} = a^{2}+ b^{2} -2ab cos(\gamma)\\\\c^{2}=18^{2}+26^{2}-2(18)(26)cos(39)\\\\ c^{2}=272.59\\\\ c=16.51

Thus the shorter diagonal will be 16.51 feet in measure.

3 0
3 years ago
What is the equation of the quadratic function represented by this table?
MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

I used logic and took the easy way around this as opposed to the long, drawn-out algebraic way.  I noticed right off that at x = -3 and x = -1 the y values were the same.  In the middle of those two x-values is -2, which is the vertex of the parabola with coordinates (-2, 4).  That's the h and k in the formula I'm going to use.  Then I picked a point from the table to use as my x and y in the formula I'm going to use.  I chose (0, 3) because it's easy.  The formula for a quadratic is

y=a(x-h)^2+k

and I have everything I need to solve for a.  Filling in my h, k, x, and y:

3=a(0-(-2))^2+4  and

3=a(2)^2+4  and

-1 = 4a so

a=-\frac{1}{4}

In work/vertex form the equation for the quadratic is

y=-\frac{1}{4}(x+2)^2+4

In standard form it's:

y=-\frac{1}{4}x^2-x+3

8 0
3 years ago
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