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4 years ago

10

The perimeter of the figure is 31m. what is the length of the missing side? 6m 8m 10m ?m

1 answer:

anyanavicka [17]4 years ago

6 0

7m would be the length to the missing side. Hope I helped

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Help me on this worksheet and pls show work :)

baherus [9]

What you do to solve this problem you put the faction side-by-side then see what number 16 and six could both go into just multiply 6 times 116 times one and keep on going down to you have the same answer doesn't answer you get is going to be a denominator and then after you get your denominator you do 5 times five and the number you get for you denominator

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3 years ago

What is 3x-15+6x+2=45

kipiarov [429]

Answer:

x=58/9 fraction x=6 4/9

Step-by-step explanation:

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3 years ago

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Which of these functions could have the graph shown below?

Blizzard [7]

B according to picture

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3 years ago

When 5 is added to a certain number and the result is multiplied by 3 the final answer is 27 what is the original number

Katyanochek1 [597]

Answer:

The original number is 4

Step-by-step explanation:

Let x be the number.

5 is added to x => 5+x

When it is multiplied by 3,

3*(5+x) = 27

=> 15 + 3x = 27

Subtract 15,

3x = 27 - 15 = 12

Divide by 3,

x = 4

3 0

3 years ago

Read 2 more answers

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams. The combined weight of one die

olya-2409 [2.1K]

Answer:

The total weight of one die, one ball, and one marble is 75 grams.

Step-by-step explanation:

Consider the provided information.

Let d represents the number of dice, b represents the number of balls and m represents the number of marbles.

So according to the question.

The combined weight of 2 identical dice, 5 identical balls and 4 identical marbles was 260 grams.

$2d+5b+4m=260$ ....(1)

The combined weight of one die and one marble was 55 grams.

$d+m=55$

$m=55-d$ ....(2)

3 balls weighed the same as two dice.

$3b=2d$

Multiply both sides by 5 and divide by 3.

$5b=\frac{10}{3}d$ .....(3)

Now put the value of equation 2 and 3 in equation 1.

$2d+\frac{10}{3}d+4(55-d)=260$

$2d+\frac{10}{3}d+220-4d=260$

$\frac{6d+10d-12d}{3}=40$

$4d=120$

$d=30$

Put d=30 in equation 2.

$m=55-30$

$m=25$

Put d=30 in equation 3.

$5b=\frac{10}{3}\times 30$

$5b=100$

$b=20$

The total weight (in grams) of one die, one ball, and one marble is:

$d+m+b=25+20+30$

$d+m+b=75$

The total weight of one die, one ball, and one marble is 75 grams.

8 0

3 years ago