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marissa [1.9K]
4 years ago
12

6m - 2(7 + 3m) > 5(2m-3) - m

Mathematics
1 answer:
taurus [48]4 years ago
7 0

6m-2(7+3m) > 5(2m-3)-m\ \ \ |\text{use distributive property}\\\\6m+(-2)(7)+(-2)(3m) > (5)(2m)+(5)(-3)-m\\\\6m-14-6m > 10m-15-m\ \ \ \ |\text{use commutative property}\\\\6m-6m-14 > 10m-m-15\\\\-14 > 9m-15\ \ \ \ |\text{add 15 to both sides}\\\\1 > 9m\ \ \ \ |\text{divide both sides by 9}\\\\\dfrac{1}{9} > m\to m < \dfrac{1}{9}\to\boxed{B.\ \left\{m|m < \dfrac{1}{9}\right\}}

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9x-y=5<br> 7x-6y=5<br> Solve the system by the substitution method
qwelly [4]
  9x - y = 5
7x - 6y = 5

Solve both equations for one variable. I'll solve for y.

9x - y = 5            Subtract 9x from both sides
      -y = -9x + 5   Divide both sides by -1
       y = 9x - 5

7x - 6y = 5   Subtract 7x from both sides
      -6y = -7x + 5   Divide both sides by -6
          y = \frac{7}{6}x - \frac{5}{6}

Since both equations equal y, you can set them equal to each other and solve for x.

9x - 5 =<span> \frac{7}{6}x - \frac{5}{6}   Multiply both sides by 6 to eliminate the fractions
54x - 30 = 7x - 5    Subtract 7x from both sides
47x - 30 = -5          Add 30 to both sides
       47x = 25          Divide both sides by 47
           x = </span>\frac{25}{47}

Now, plug that x-value into the x of either equation. I'll plug it into 9x - y = 5.

9x - y = 5   Plug in the x-value
9(<span>\frac{25}{47}) - y = 5   Multiply
</span>\frac{225}{47} - y = 5   Subtract <span>\frac{225}{47} from both sides
</span>-y = <span>0.21276595744 (I had to convert it to a decimal)   Divide both sides by -1
 y = -</span><span>0.21276595744

So, the answer to the system is (</span>0.53191489361, -<span>0.21276595744)</span>
8 0
4 years ago
Please help me with number 3.<br> 100 points plus Brainly five stars ⭐️ and a thanks
Elis [28]

Answer:

10 and 7

Step-by-step explanation:

First you can list out numbers 1-10 and find thngs that equal 3 when subtracted. Then after you do that see if when you multiply y x 3 subtracted from x if it equals -11.

10-7 =3

10 - (7x3)

10 - 21

-11

8 0
2 years ago
Rearrange the formula S = a (a - r) for r.
koban [17]
I'm assuming you're trying to solve for r.
First divide a to both sides
Now you have \frac{S}{a} = a - r
Subtract a to both sides.
And then divide by -1 to both sides.
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8 0
4 years ago
Read 2 more answers
What is the sum of (7-b)+(3b+2)
nadezda [96]
(7 - b) + (3b + 2)

Open the parentheses (this is a simple addition question so there's no need to do anything)

7 - b + 3b + 2

Rearrange (not necessary but makes it easier)
3b - b + 7 + 2
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-T.B.
4 0
3 years ago
8. For many computer tablets, the owner can set a 4-digit pass code to lock the device.
Anton [14]

Answer:

a. There 5040 different pass codes if the digits cannot be repeated

b. The probability that the pass code is 1234 is ≈ 0.0002

c.  The probability that two people both have a pass code of 1234 is 4×10^{-8}

Step-by-step explanation:

a. How many different 4-digit pass codes are possible if the digits cannot be repeated?

There are

  • 10 possibilities for the first digit
  • 9 possibilities for the second digit
  • 8 possibilities for the third digit
  • 7 possibilities for the fourth digit

Thus there are  10×9×8×7=5040 different pass codes

b. If the digits of a pass code are chosen at random and without replacement from the digits, what is the probability that the pass code is 1234

The probability that the first digit is 1 is \frac{1}{10}

The probability that the second digit is 2 is \frac{1}{9}

The probability that the second digit is 3 is \frac{1}{8}

The probability that the fourth digit is 4 is \frac{1}{7}

Thus  the probability that the pass code is 1234 is \frac{1}{10} * \frac{1}{9} *\frac{1}{8} *\frac{1}{7} =\frac{1}{5040} ≈ 0.0002

c. The probability that two people, who both chose a pass code by selecting digits at random and without replacement, both have a pass code of 1234?

The probability that the pass code of the one person is 1234 is 0.0002

The probability that the pass code of the other person is 1234 is 0.0002

Thus, the probability that two people have both pass code of 1234 is

0.0002×0.0002 = 4×10^{-8}

3 0
4 years ago
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