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WINSTONCH [101]
4 years ago
14

The sum of 2 numbers is 14Both numbers are less than ten and their difference is 2What is the smaller of the two numbers?

Mathematics
2 answers:
docker41 [41]4 years ago
8 0

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Let the numbers be A and B

Given

The sum of both numbers = 14

So

A + B = 14

Also, the difference between the numbers = 2

That’s

A - B = 2

So ,we now have two equations

1. A + B = 14

2. A - B = 2

Add both equations to eliminate B. B + (-B) = B - B = 0

So we have

2A = 16

Divide both sides by 2 to get A

2A/2 = 16/2

A = 8

Now substitute 8 for A in either equation to get B

Using equation 1 , we have

A + B = 14

8 + B = 14

Subtract 8 from both sides to isolate B

8 - 8 + B = 14 - 8

B = 6

The two numbers are 8 and 6.the smaller number is 6

BaLLatris [955]4 years ago
7 0
The numbers are 8 and 6. the smaller number would be 6
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Find the length of the height of the right trapezoid shown below, if it has the greatest possible area and its perimeter is equa
Artyom0805 [142]

Answer:

The height of the right trapezoid is   \frac{6}{5+\sqrt{3}}\ units

Step-by-step explanation:

Let

x ----> the height of the right trapezoid in units

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+DH+HA

we have

P=6\ units

AB=BC=CH=HA=x ---> because is a square

substitute

6=x+x+CD+DH+x

6=3x+CD+DH -----> equation A

<em>In the right triangle CDH</em>

sin(30\°)=\frac{CH}{CD}

sin(30\°)=\frac{1}{2}

so

Remember  that CH=x

\frac{1}{2}=\frac{x}{CD}

CD=2x

tan(30\°)=\frac{CH}{DH}

tan(30\°)=\frac{\sqrt{3}}{3}

so

\frac{\sqrt{3}}{3}=\frac{x}{DH}

DH=x\sqrt{3}

substitute the values in the equation A

6=3x+CD+DH -----> equation A

CD=2x

DH=x\sqrt{3}

6=3x+2x+x\sqrt{3}

6=5x+x\sqrt{3}

6=x[5+\sqrt{3}]

x=\frac{6}{5+\sqrt{3}}\ units

5 0
3 years ago
A line segment with endpoints A(-2, 1) and B (2, 1) is dilated with a dilation centered at the origin and a scale factor of
lesya692 [45]

Answer:

Step-by-step explanation:

I will assume that the scale factor is 2.5

A'(-5,2.5)   True

AB || A'B'   True

?? What does ABAB" mean?

A'B' is an enlargement of AB   True

8 0
3 years ago
3
Ksju [112]

Answer:

2 i think

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What's the value of x? 40000mg =10x g
dybincka [34]

The value of x is 4. So 40000 mg= 40 g.

Step-by-step explanation:

      The given is 40000mg = 10x g

Step:1

      Take given equation as equation (1)

                     40000 mg= 10x g.................(1)

      where, X is known value.

Step:2

      Standard value for mg to g for the purpose of conversion of units,

                      1 milligram = 0.001 gram   (or)

                      1 gram = 1000 milligram

Step:3

      From the standard data values,

                    = 40000 mg

      it converted mg to g by dividing 1000

                    = \frac{40000}{1000} g

                    = 40 g.......................(2)

Step:4

       From the Equations (1) and (2),

                 40=10x

                  x=4

Result:

       The value of x is 4. So, 40000mg = 40 g.

7 0
3 years ago
the figure below is a square . Find the length of side x in simplest radical form with a rational denominator.
wel

Answer:

\sqrt{14}

Step-by-step explanation:

In any square with side length s, the diagonal of the square is equal to s\sqrt{2}. Since the side length of this square is \sqrt{7}, the diagonal is equal to \sqrt{7}\cdot \sqrt{2}=\boxed{\sqrt{14}}.

Alternatively, you can form two 45-45-90 triangles with the diagonal of the square. The diagonal acts as the hypotenuse for the both these triangles, and the legs of both triangles are equal to the side length of the square. To find the length of the diagonal, use the Pythagorean Theorem, which states a^2+b^2=c^2, where c is the hypotenuse of the triangle, and a and b are the two legs of the triangle.

In this question, both legs are equal to \sqrt{7}, and we're solving for the diagonal, which is the hypotenuse in this case:

\sqrt{7}^2+\sqrt{7}^2=c^2,\\c^2=14,\\c=\boxed{\sqrt{14}}

4 0
3 years ago
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