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Readme [11.4K]
3 years ago
9

I need help please???

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

option 4 .x<11 is the correct answer

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A professor gives a statistics exam. The exam has 100 possible points. The scores for the students in the second classroom are a
Vesna [10]

Answer:

N = 9

M = 87.11

Step-by-step explanation:

According to the situation, the data provided and the solution are as follows

The scores for the student in the classroom is

= 88 88 92 88 88 72 96 88 84

The different student's number of scores is 9

The solution of new n and M is shown below:-

Sample size (n) = 9

Sample mean (m) is

= \frac{Sum\ of\ all\ data\ values}{Sample\ size}

= \frac{88 + 88 + 92 + 88 + 88 + 72 + 96 + 88 + 84}{9}

= \frac{784}{9}

= 87.11

3 0
3 years ago
(8d+4)–(d+2)<br><br> Subtract
icang [17]

Answer:

7d+2

Step-by-step explanation:

:)

6 0
3 years ago
Read 2 more answers
Which number gives you an irrational product when you multiple it by 0.2
Vinil7 [7]
Is the question complete or is that 0.25?
6 0
3 years ago
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How to simplify 4d + 3x - d + 2x
Vanyuwa [196]
You just combine like terms
So 4d + - d = 3d
And 3x + 2x = 5x
So the answer is 3d + 5x
7 0
3 years ago
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What is the maximum number of possible extreme values for the function,
Liula [17]

Answer:

<h2>(0.3, -18.45).</h2>

Step-by-step explanation:

We need to recur to the extreme value theorem, which states: "If a function is continuous on a closed interval, then that function has a maximum and a minimum inside that interval".

Basically, as the theorem states, if a dunction is continuous, then it has maxium or minium.

In this case, we have a quadratic function, which is a parabola. An important characteristic of parabolas is that they have a maximum or a minium, but they don't have both. When the quadratic term of the fuction is positive, then it has a minium at its vertex. When the quadratic term of the function is negative, then it has a maximum at its vertex.

So, the given function is f(x)=x^{2} +4x^{2} -3x-18=5x^{2} -3x-18, where the quadratic term is positive, so the functions has a minimum at V(h,k), where h=-\frac{b}{2a} and k=f(h), let's find that point

<h3>h=-\frac{-3}{2(5)} =\frac{3}{10} =0.3</h3><h3>k=f(0.3)=5(0.3)^{2} -3(0.3)-18=0.45-0.9-18=-18.45</h3><h3 /><h3>Therefore, the minium of the function is at (0.3, -18.45).</h3>
8 0
3 years ago
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