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Charra [1.4K]
3 years ago
7

A distribution of measurements is relatively mound-shaped

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0
\mathbb P(X>60)=\mathbb P\left(\dfrac{X-50}{10}>\dfrac{60-50}{10}\right)=\mathbb P(Z>1)

Since approximately 68% of a (roughly) normal distribution falls within one standard deviation of the mean, that leaves 32% that falls outside, and by symmetry 16% should lie above one standard deviation of the mean.
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