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sattari [20]
3 years ago
11

Divide. (18x^3+12x^2-3x)/6x^2

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
The answer to the first one is C

Second part is  x^2 - 12  (B)


aleksley [76]3 years ago
8 0

Answer:

1. The correct option is C.

2. The correct option is B.

Step-by-step explanation:

1.

The given expression is

\frac{18x^3+12x^2-3x}{6x^2}

Simplify the expression,

\frac{18x^3}{6x^2}+\frac{12x^2}{6x^2}-\frac{3x}{6x^2}

Cancel out the common factors.

3x+2-\frac{1}{2x}

Therefore option C is correct.

2.

The given expression is

\frac{2x^3-x^2-24x+12}{2x-1}

Use grouping method to simplify the numerator.

\frac{x^2(2x-1)-12(2x-1)}{2x-1}

\frac{(2x-1)(x^2-12)}{2x-1}

Cancel out the common factors.

x^2-12

Therefore option B is correct.

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Construct Equation :
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Sum of these numbers is 72
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Solve for x :
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3rd number = x + 2 = 23 + 2 = 25

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Answer : The numbers are 23, 24 and 25.
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