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sattari [20]
3 years ago
11

Divide. (18x^3+12x^2-3x)/6x^2

Mathematics
2 answers:
iren [92.7K]3 years ago
8 0
The answer to the first one is C

Second part is  x^2 - 12  (B)


aleksley [76]3 years ago
8 0

Answer:

1. The correct option is C.

2. The correct option is B.

Step-by-step explanation:

1.

The given expression is

\frac{18x^3+12x^2-3x}{6x^2}

Simplify the expression,

\frac{18x^3}{6x^2}+\frac{12x^2}{6x^2}-\frac{3x}{6x^2}

Cancel out the common factors.

3x+2-\frac{1}{2x}

Therefore option C is correct.

2.

The given expression is

\frac{2x^3-x^2-24x+12}{2x-1}

Use grouping method to simplify the numerator.

\frac{x^2(2x-1)-12(2x-1)}{2x-1}

\frac{(2x-1)(x^2-12)}{2x-1}

Cancel out the common factors.

x^2-12

Therefore option B is correct.

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Answer:

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Step-by-step explanation:

So consecutive integers, just means they're separated by a value of 1. This can be generally expressed as "a, a+1" where these two values would be consecutive integers assuming "a" is an integer.

So let's express Hassan's age as the variable "x", since it's unknown. Since Cameron is older, and by definition of a consecutive integer, Cameron's can be expressed as "x+1"

So the equation we need to set up is Cameron's age + 5(Hassan's age) = 145

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Distribute the 5: x+1+5x

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Since we used "x" to represent Hassan's age, Hassan's age is 24. Since we used "x+1" to represent Cameron's age, Cameron's age is "24+1" which is just 25

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Hey there!

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