Right isosceles triangle <3
Its a right triangle, and the two sides are equal so its isosceles
The answer is: " 2291 units " .
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Explanation:
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Formula for "Area of a trapezoid" :
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Area = (1/2) * (base length 1 + base length 2) * height;
or: A = (1/2) * (b + B) * h.
We are missing the value for "b" one of the base lengths.
However, since: A = 68² (given) ; B (the other base length) = 21; and the perpendicular height, "h" = 4 ; we can plug this values into the formula, and solve for "b" ;
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A = (1/2) * (b + B) * h ; ↔ 68² = (1/2) * (b + 21) * 4 ;
↔ <span>4624 = 2 (b + 21) = 2b + 42 ;
</span> ↔ <span>4624 = 2b + 42 ;
</span> ↔ <span>2b + 42 = 4624 ;
Subtract "42" from each side of the equation:
2b + 42 - 42 = 4624 - 42 ;
to get: 2b = 4582 ;
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Now, divide each side of the equation by: "2" ; to isolate "b" on one side of the equation; and to solve for "b" ;
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2b / 2 = 4582 / 2 ;
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to get: b = 2291 units.
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The correct option is D.
Option A. isn't even about quadrilater, so we can immediately discard it.
Option B. statement is true, but has nothing to do with the point of the question. In fact, it is true that every square is in particular a rectangle, but in turn every rectangle is a parallelogram. So, there's no counterexample here
Option C. is false, because a dart is a parallelogram: both of its opposite sides are parallel.
Option D. finally presents a counterexample. In fact, The two bases of a trapezoid are parallel, but the two other sides are not. So, a trapezoid is not a parallelogram, even though it has a pair of parallel sides. This is way, in order to be a parallelogram, it is necessary for the quadrilateral to have two pairs of parallel sides.
