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olga nikolaevna [1]
3 years ago
9

Please help with this as soon as possible​

Mathematics
2 answers:
Rashid [163]3 years ago
8 0

Answer:

Step-by-step explanation:

Factorize all the numbers in numerator and denominator

16 = 2*2*2*2

125 = 5 *5 *5

\frac{a^{m}}{a^{n}}=a^{m-n},  where m >n

\frac{5^{4}*7^{5}*2^{8}}{16*125*7^{3}}=\frac{5^{4}*7^{5}*2^{8}}{2^{4}*5^{3}*7^{3}}\\\\\\=5^{(4-3)}*7^{(5-3)}*2^{(8-4)}\\\\\\=5^1*7^2*2^{4}

yulyashka [42]3 years ago
5 0

Answer:

98,000

Step-by-step explanation:

5^{4} *7^{5}* 2^{8}/16*125*7^{3}

=5^{4} * 7^{5}* 2^{8}  /2^{4} *5^{3} *7^{3}

=5^{4-1} *7^{5-3} *2^{8-4}

=5^{3} *7^{2} *2^{4}

=125*49*16

=98000

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