Question

Please help with this as soon as possible​

Answer 1

Answer:

Step-by-step explanation:

Factorize all the numbers in numerator and denominator

16 = 2*2*2*2

125 = 5 *5 *5

$\frac{a^{m}}{a^{n}}=a^{m-n}$,  where m >n

$\frac{5^{4}*7^{5}*2^{8}}{16*125*7^{3}}=\frac{5^{4}*7^{5}*2^{8}}{2^{4}*5^{3}*7^{3}}\\\\\\=5^{(4-3)}*7^{(5-3)}*2^{(8-4)}\\\\\\=5^1*7^2*2^{4}$

Answer 2

Answer:

98,000

Step-by-step explanation:

$5^{4} *7^{5}* 2^{8}/16*125*7^{3}$

$=5^{4} * 7^{5}* 2^{8} /2^{4} *5^{3} *7^{3}$

$=5^{4-1} *7^{5-3} *2^{8-4}$

=$5^{3} *7^{2} *2^{4}$

=$125*49*16$

$=98000$