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Leno4ka [110]
3 years ago
5

What are the odds of spinning red on the spinner shown?

Mathematics
2 answers:
mestny [16]3 years ago
5 0
Well the odds of red is 40%-60% because they are two reds in the wheel.
zmey [24]3 years ago
3 0

Answer:

The answer in fractional form is 2/4, or 1/2

Step-by-step explanation:

The formula for odds is:

favorable outcomes/unfavorable outcomes

So, there are 2 reds (favorable) and 4 other colors (unfavorable)  =2/4

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The answer is 6,5 on the graph
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Connor starts from a cliff that is 200 feet above the canyon floor and climbs down at an average speed of 10 feet per minute.
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Not worth it

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Jim and Abby each bought burgers and fries from the concession stand at the fair. Jim bought 3 burgers and 2 orders of fries for
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Answer:

Jim bought 3 burgers for $5.50 & 2 orders of fries for $3.00. Abby bought 2 burgers for $9.00 and 4 orders of fries for $5.00.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
If f(x)f(x) is an exponential function where f(-0.5)=27f(−0.5)=27 and f(1.5)=21f(1.5)=21, then find the value of f(0.5)f(0.5), t
vovikov84 [41]

Given:

f(x) is an exponential function.

f(-0.5)=27

f(1.5)=21

To find:

The value of f(0.5), to the nearest hundredth.

Solution:

The general exponential function is

f(x)=ab^x

For, x=-0.5,

f(-0.5)=ab^{-0.5}

27=ab^{-0.5}          ...(i)

For, x=1.5,

f(1.5)=ab^{1.5}

21=ab^{1.5}          ...(ii)

Divide (ii) by (i).

\dfrac{21}{27}=\dfrac{ab^{1.5}}{ab^{-0.5}}

\dfrac{7}{9}=b^2

Taking square root on both sides, we get

\dfrac{\sqrt{7}}{3}=b

b\approx 0.882

Putting b=0.882 in (i), we get

27=a(0.882)^{-0.5}

27=a(1.0648)

\dfrac{27}{1.0648}=a

a\approx 25.357

Now, the required function is

f(x)=25.357(0.882)^x

Putting x=0.5, we get

f(0.5)=25.357(0.882)^{0.5}

f(0.5)=23.81399

f(0.5)\approx 23.81

Therefore, the value of f(0.5) is 23.81.

6 0
3 years ago
What is the axis of symmetry for the function f(x)=7-4x+x2?<br> X=-3<br> x = -2<br> x = 2<br> x= 3
Vilka [71]

Answer: it’s C.) X= 2

Step-by-step explanation:

6 0
3 years ago
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