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2 years ago

What are the odds of spinning red on the spinner shown?

Mathematics

2 answers:

mestny [16]2 years ago

5 0

Well the odds of red is 40%-60% because they are two reds in the wheel.

zmey [24]2 years ago

3 0

Answer:

The answer in fractional form is 2/4, or 1/2

Step-by-step explanation:

The formula for odds is:

favorable outcomes/unfavorable outcomes

So, there are 2 reds (favorable) and 4 other colors (unfavorable) =2/4

You might be interested in

Given the function g(x) = x2 + 5x + 1, determine the average rate of change of

Elden [556K]

Answer:

-6

Step-by-step explanation:

The average rate of change of a function, f(x), on interval [a,b] is (f(b)-f(a))/(b-a).

So the avereage rate of change of a function, f(x)=x^2+5x+1, on [-9,-2] is

(f(-2)-f(-9))/(-2--9)

(f(-2)-f(-9))/(7)

Stop!

To find f(-2), you replace x in f(x) = x^2 + 5x + 1, with (-2) giving you f(-2)=(-2)^2+5(-2)+1=4-10+1=-6+1=-5.

To find f(-9), you replace x in f(x) = x^2 + 5x + 1, with (-9) giving you f(-2)=(-9)^2+5(-9)+1=81-45+1=36+1=37.

Continue!

(f(-2)-f(-9))/(7)

=(-5-37)/7

=(-42)/7

=-42/7

=-6

6 0

2 years ago

WILL GIVE BRAINLIEST!

Dafna11 [192]

Answer:

(a) $6550

(b) $1511.54

Step-by-step explanation:

(a) You can solve the equation

... 12 × (monthly salary) = $78,600

by dividing both sides of the equation by 12.

... (monthly salary) = $78,600/12 = $6,550

(b) You know there are 52 weeks in a year, so you know that ...

... 52 × (weekly salary) = $78,600

... (weekly salary) = $78,600/52 ≈ $1,511.54 . . . . . . . divide by 52

5 0

3 years ago

A seamstress needs to cut 15 inches pieces of ribbon from a roll of ribbon that is 9 feet in length what is the greatest number

Natali [406]

Answer: 36

Step-by-step explanation:

One roll is of length = 9 feet

1 foot = 12 inches

9 feet = 12 *9 = 108 inches

Since there are 5 rolls

So, total length of 5 rolls = 108 * 5 = 540 inches

Since we are given that A seamstress needs to cut 15-inch pieces of ribbon from a roll of ribbon that is 9 feet in length.

We are supposed to find . What is the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon

So, number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon:

Hence the greatest number of 15-inch pieces the seamstress can cut from 5 of these rolls of ribbon is 36

4 0

3 years ago

Find the area of the surface correct to four decimal places by expressing the area in terms of a single integral and using your

love history [14]

If we substitute $x=r\cos\theta$ and $y=r\sin\theta$ , we get $r^2=x^2+y^2$ , so that

$z=\cos(x^2+y^2)=\cos(r^2)$

which is independent of $\theta$ , which in turn means the surface can be treated like a surface of revolution.

Consider the function $f(t)=\cos(t^2)$ defined over $0\le t\le1$ . Revolve the curve $C$ described by $f(t)$ about the line $t=0$ . The area of the surface obtained in this way is then

$\displaystyle2\pi\int_C\mathrm dS=2\pi\int_0^1\sqrt{1+f'(t)^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+(-2t\sin(t^2))^2}\,\mathrm dt$

$=\displaystyle2\pi\int_0^1\sqrt{1+4t^2\sin^2(t^2)}\,\mathrm dt\approx7.4144$

4 0

2 years ago

Which of the following is not a possible number of solutions when solving a system of equations containing a quadratic and a lin

Kobotan [32]

Answer:

Step-by-step explanation:

We have a system with two equations, one equation is a quadratic function and the other equation is a linear function.

To solve this system we have to clear "y" in both equations, and then equal both equations, then we will have a quadratic function and equal it to zero:

$ax^2+bx+c=0, a\neq 0$

Then to resolve a quadratic equation we apply Bhaskara's formula:

$x_{1}=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x_{2}=\frac{-b-\sqrt{b^2-4ac} }{2a}$

It usually has two solutions.

But it could happen that $\sqrt{b^2-4ac}$ then the equation doesn't have real solutions.

Or it could happen that there's only one solution, this happen when the linear equation touches the quadratic equation in one point.

And it's not possible to have more than 2 solutions. Then the answer ir 3.

For example:

In the three graphs the pink one is a quadratic function and the green one is a linear function.

In the first graph we can see that the linear function intersects the quadratic function in two points, then there are two solutions.

In the second graph we can see that the linear function intersects the quadratic function in only one point, then there is one solutions.

In the third graph we can see that the linear function doesn't intersect the quadratic function, then there aren't real solutions.

7 0

3 years ago