Question

Two planes simultaneously left the Washington and LA and headed towards each other. The distance between the cities is 2700 miles. After they flied for 2 hours, they have not met each other yet, and distance between them was still 500 miles. What is the speed of each plane, if the one from LA was 100 mph faster?

Answer 1

Answer:

Washington plane = 500 mph

LA plane = 600 mph

Step-by-step explanation:

Speed of Washington plane(mph) = w

Speed of LA plane(mph) = w + 100

2700 - 2(w + w + 100) = 500

2700 - 2(2w + 100) = 500

2200 - 4w - 200 = 0

4w + 200 = 2200

4w = 2000

w = 500

w + 100 = 600

Answer 2

Answer:a = 500 miles per hour

b = a + 100= 600 miles per hour

Step-by-step explanation:

Let a be speed of plane flying from Washington

distance moved after 2 hrs =2a

Let b be speed of plane flying from LA

distance moved after 2 hrs =2b

2a + 2b + 500 = 2700

2a + 2b = 2200 --------1

b = a + 100 (plane from LA is faster)

2a + 2(a+100) = 2200

4a = 2000

a = 500 miles per hour

b = a + 100= 600 miles per hour