What is the greatest perimeter of a rectangle with an area of 39 ft.²
1 answer:
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Answer:
5.85 m
Step-by-step explanation:
The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:
<u>Where:</u>
Ag: is the area of the rectangular garden
a: is the length of the rectangular garden = 50 cm = 0.5 m
b: is the width of the rectangular garden = 34 m
<u>Where</u>:
As: is the area of the sand road
The relation between the area of the sand road and the area of the rectangular garden is the following:
By solving the above equation for x we have two solutions:
x₁ = -23.10 m
x₂ = 5.85 m
Taking the positive value, we have that the width of the sand road is 5.85 m.
I hope it helps you!
The area of the rectangular patio to be painted is: B. A = (x + 20)(x + 10) - 12.
<h3>What is a Rectangle?</h3>A rectangle, by definition, is a quadrilateral with two pairs of opposite that have the equal lengths. All four angles of a rectangle are right angles (90 degrees).
<h3>What is the Area of a Rectangle?</h3>The area of a rectangle = (length of rectangle)(width of rectangle).
Given the following parameters for the patio and the bench:
- Length of rectangular patio = x + 20
- Width of rectangular patio = x + 10
- Length of rectangular bench = 6
- Width of rectangular bench = 2
Area to be painted = area of rectangular patio - area of rectangular bench
Area of rectangular patio = (x + 20)(x + 10)
Area of rectangular bench = (6)(2) = 12
Area to be painted = (x + 20)(x + 10) - 12
The answer is: B. A = (x + 20)(x + 10) - 12.
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