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blsea [12.9K]
3 years ago
7

The inequality x < 9 or x ≥ 14 can be used to represent the hourly wage, x, of each employee at a store. Which are possible v

alues for x? Select two options. $8 $9 $11 $13 $14
Mathematics
2 answers:
prisoha [69]3 years ago
4 0

Answer:

<h2>$11 and $13 </h2>

Step-by-step explanation:

Given the two inequalities  x < 9 or x ≥ 14 used to represent the hourly wage, x, of each employee at a store, to determine the possible value of x, we must first know the range of x.

From the inequality x ≥ 14, taking the reciprocal of both sides will change the sense of the inequality as shown;

1/x ≤ 1/14

cross multiplying will givw;

14≤x ... 1

Combining both equation 1 and the inequality x< 9 will give;

14≤x9

This inequality shows that the value of x falls with the range of 9 and 14 inclusive. The range of values are 14, 13, 12, 11 and 10.

From the above range of values, the possible value of x will be $11 and $13. <em>x may or may not be equal to $14 so we can ignore $14</em>

CaHeK987 [17]3 years ago
3 0

Answer:

$8 and $14

Step-by-step explanation:

I took the quiz and this is the right answer.

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Plz help don’t understand
saul85 [17]

Answer:

Step-by-step explanation:

every time x goes up 1,  y goes up 4  

x = 3  minus x = 2  is a delta (a change of 1)

x = 4  minus x = 3  is a delta (a change of 1)

x = 5  minus x = 4  is a delta (a change of 1)

       the delta x is ALWAYS 1 for this table you can always substract x's to find the delta     delta is symbolized by Δ      Δx  for the delta x

y = 7  minus y = 3  is a delta (a change of 4)

y = 11  minus y = 7  is a delta (a change of 4)

y = 15  minus y = 11  is a delta (a change of 4)

    the delta y is ALWAYS 4 for this table you can always substract y's to find the delta     delta is symbolized by Δ     Δy  for the delta y

the slope m = Δy / Δx      m = 4 / 1     m = 4

     y = mx + b             when x = 0    then  y = b   (called the y intercept)

so how do we find the y intercept?    

look at the pattern in the TABLE  Δx  and Δy

   when x = 1    y = (3 - 4)  = -1

             x = 0    y =( -1 - 4)   = -5

so       y = 4x - 5     is a line equation for the data in this table

                                I believe there are other forms for linear equations

                               I chose the y-intercept form

use the point slope equation

       (y - y1)  =  m(x - x1)            where (x1, y1)  are the coordinates of a point on  

                                                the line

       when you know the slope of the line and a point on the line

       as before

       m = (y2 - y1)  / (x2 - x1)          from the table

           = (7 - 3) / (3 - 2)                 still equals

           = 4/1  =  4        

        pick a point on the line    say x= 4 and y = 11    (4, 11)

       (y - y1)  =  m(x - x1)    

        y - 11   =   4(x - 4)              point slope form

         solving point slope form  for  y

        y  - 11  =   4x - 16               add 11 to both sides    

           y  =  4x - 5                    back to the y-intercept form

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Step-by-step explanation:

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