The area of a <span>isosceles triangle:
S=(bh)/2, where b is for base (=4) and h is for height (=x+3)
We get the equation:
10=(4*(x+3))/2
10=(4x+12)/2
4x+12=20
4x=8
x=2
</span>
theta is in the fourth quadrant where the cosine is positive.
the third side in the triangle = sqrt (4 - 2) = sqrt2
So sin theta = -sqrt2/2 = Second choice (negative because sine is negative in 4th quadrant)
tan theta = - sqrt2 / sqrt2 = -1
Step-by-step explanation:
first u find the angles and then u use some low divide the length of triangle by sin of opposite angles
Acceleration is simplified by assuming it is the constant -g
a=-g we integrate this with respect to time to get v...
v=-gt+C where C is the initial velocity in this case 14ft/s so
v=-gt+14 integrate again to get the height function
h=(-gt^2)/2 +14t +C we are not given an initial height so C is 0
h(t)=14t-gt^2/2 letting g=32 and neatening up a bit...
h(t)=14t-16t^2
