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Allisa [31]
3 years ago
6

Andrew and Connie are both teachers at their local school. There are 15 female teachers at the school and 35 male teachers. What

is the ratio of male to female teachers?
Mathematics
1 answer:
wlad13 [49]3 years ago
3 0

Answer:

7:3

Step-by-step explanation:

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Jeremy used 11 gallons and 3 quarts of water to water his garden. How many quarts of water did Jeremy use?
Anon25 [30]

Answer:

47

Step-by-step explanation:

since each gallon is 4 quarts you would multiply by 11. 44 quarts then add 3 extra quarts to get 47

6 0
3 years ago
If the first term is 5 and the common difference is -3?
Doss [256]
-2 is the answer
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6 0
3 years ago
A birthday party host planned for 20 people, but 17 actually attended. What is the percent error?​
Nikolay [14]

Answer: 29% i believe is the answer

8 0
3 years ago
Read 2 more answers
Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap
pantera1 [17]

Answer:

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e \dfrac{dV}{dt}= 20 \ ft^3/min

we know that radius r is always twice the   diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

V = \dfrac{\pi r^2 h}{3}

V = \dfrac{\pi (h/2)^2 h}{3}

V = \dfrac{1}{12} \pi h^3

V = \dfrac{ \pi h^3}{12}

Taking the differentiation of volume V with respect to time t; we have:

\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}

\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}

we know that:

\dfrac{dV}{dt}= 20 \ ft^3/min

So;we have:

20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}

20= 56.25 \pi \times \dfrac{dh}{dt}

\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

The height of the pile is increasing at the rate of  \mathbf{ \dfrac{20}{56.25 \pi}   \ \ \ \ \  ft/min}

8 0
3 years ago
A submarine dives at a constant speed of 10 m/s at a diving angle measured from the vertical
valina [46]

Answer:

155.3 m

Step-by-step explanation:

<u>We have:</u>

θ: is the angle measured from the vertical = 75 °

v = is the speed of the submarine = 10 m/s

t = 1 min

The deep of the front end of the submarine at the end of a 1-minute drive is given by the following ratio:

cos (\theta) = \frac{x}{d}  

<u>Where:</u>

d: is the distance traveled by the submarine in 1 minute

x: is the deep to find

The distance, d, is:

d = v*t = 10 \frac{m}{s}* 1 min * \frac{60 s}{1 min} = 600 m

Now, the deep is:

cos (75) = \frac{x}{600}  

x = cos(75)*600 = 155.3 m

Therefore, the deep of the front end of the submarine at the end of a 1-minute drive is 155.3 m.

I hope it helps you!

3 0
3 years ago
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