The Total surface area of the rectangular prism = 168 in.²
The Volume of the rectangular prism = 108 in.³
<h3>What is the Total Surface Area of a Rectangular Prism?</h3>
The total surface area of a rectangular prism is given as: SA = 2(wl + hl + hw), where:
w = width of the rectangular prism
h = height of the rectangular prism
l = length of the rectangular prism
<h3>
What is the Volume of a Rectangular Prism?</h3>
The volume of a rectangular prism = l × w × h
Find the Total surface area of the rectangular prism:
Length (l) = 9 in.
Width (w) = 2 in.
Height (h) = 6 in.
Total surface area of the rectangular prism = 2(wl+hl+hw) = 2·(2·9+6·9+6·2) = 168 in.²
Find the volume of the rectangular prism:
Length (l) = 9 in.
Width (w) = 2 in.
Height (h) = 6 in.
Volume of the rectangular prism = l × w × h = 9 × 2 × 6
Volume of the rectangular prism = 108 in.³
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Answer:
18:24 or simplest form is 3:4
Step-by-step explanation: If you don't need to simplify then it is 18:24, but if you simplify it by dividing 18 and 24 by 6, then the answer is 3:4 :)
Answer:8(1/2x - 1/4)> 12 - 2x
a.x > 7
b.x > 7/3
c.x > 5/3
d.x > 5/3
Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x
Answer:
In order to find the variance we need to calculate first the second moment given by:
And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

Step-by-step explanation:
Previous concepts
The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.
The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).
Solution to the problem
For this case we have the following distribution given:
X 3 4 5 6
P(X) 0.07 0.4 0.25 0.28
We can calculate the mean with the following formula:

In order to find the variance we need to calculate first the second moment given by:

And the variance is given by:
![Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20%2B%5BE%28X%29%5D%5E2%20%3D%2023.36%20-%5B4.74%5D%5E2%20%3D%200.8924)
And the deviation would be:

So what you are trying to find is the certain amount of children tickets and adult tickets. the final amount is a total of $12. This means that a unknown number of children tickets (c) times 1.50 (price of each ticket for children) plus the unknown number of adult tickets (a) times 4.00 (price of each ticket for adults) equals a final cost of $12.00.
Equation: 1.50c+4.00a= 12.00