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12345 [234]
3 years ago
8

WILL GIVE BRAINLIEST ANSWER TO WHOEVER IS ABLE TO FULLY AND CORRECTLY ANSWER THIS QUESTION. Consider and trapezoid in the follow

ing image and use them to answer the questions below. is a right triangle and trapezoid is isosceles. Do NOT use the law of cosines, use our knowledge from the content of this course. a. Describe how to find the lengths of segments and . Show your answers for this question. Explain how you can be confident your calculations are correct. b. Describe how to find the angle measures of and . Explain how you can be confident your calculations are correct. c. Are there any segments or angles you can’t calculate based solely on the information in the image? Why? d. If we drew a median into trapezoid and the given measurement of that median was 21.425, would that change your answer for part c of this question?

Mathematics
1 answer:
FinnZ [79.3K]3 years ago
7 0

This is an isosceles trapezoid, because the two angles are supplementary on the right side.

y is 25 based on the Pythagorean theorem

w is sqrt (850)=29.15

z must be 15

Making a right triangle to look at the altitude

cos 59=a/15, so a is 7.73 between the right corner and the edge of x

 

That means x is 29.15-2(7.73)=13.69

=============

The median should be half way between 13.69 and 29.15

That is half their sum, or half of 42.84 or 21.42

That doesn't change the answer above

Once I know the trapezoid is isosceles, the angles at the base have to be 59d and the angles at the top 121d.

please mark brainliest!

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Answer:

Section A holds 25,000 seats, section B holds 14,500 seats and section C holds 10,500 seats.

Step-by-step explanation:

From the information given you can write the following equations:

A+B+C=50,000 (1)

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B= number of seats in section B

C= number of seats in section C

You can replace (3) in (1) and (2) to get two equations:

B+C+B+C=50,000

2B+2C=50000

28(B+C)+24B+20C=1,258,000

28B+24B+28C+20C=1,258,000

52B+48C=1,258,000

The two equations are:

2B+2C=50000 (4)

52B+48C=1,258,000 (5)

You can isolate B in (4):

2B=50,000-2C

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B=25,000-C

Now, you can replace B in (5):

52(25,000-C)+48C=1,258,000

1,300,000-52C+48C=1,258,000

1,300,000-1,258,000=4C

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Now, you can replace the value of C in B=25,000-C:

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B=14,500

Finally, you can replace the values of B and C in A=B+C to find A:

A=14,500+10,500

A=25,000

According to this, the answer is that section A holds 25,000 seats, section B holds 14,500 and section C holds 10,500.

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