Answer:
(x-4)² + y² = 100
Step-by-step explanation:
The only circles that have a center at (4 , 0) are :
(x-4)² + y² = 100
(x-4)² + y² = 10
……………………
• (-2 - 4)² + 8² = (-6)² + 64 = 36 + 64 = 100 ≠ 10
Then
The circle (x-4)² + y² = 10 doesn’t contain the point (-2, 8)
• (-2 - 4)² + 8² = 100
Then
The circle (x-4)² + y² = 100 contains the point (-2, 8)
Answer:
Step-by-step explanation:
Use exponent rule 
:
I dunno actually D: I think it's 1.6 sorry I really don't know leave a 1 star if you have to!
(ab+3)(ab−3)
=(ab+3)(ab+−3)
=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)
=a^2b^2−3ab+3ab−9
=a^2b^2−9
1.4 / 7
multiply by 10 in both up and down
(1.4*10) / (7*10)
14 / 70
divide by 7
(14/7) / (70/7)
2 / 10
divide by 2
(2/2) / (10/2)
1 / 5
