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Xelga [282]
3 years ago
12

Please help and show work!! EVENS ONLY!! I'm really stuck!! Will mark brainliest!!

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Here ya go with work shows

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The times of the runners in a marathon are normally distributed, with a mean of 3 hours and 50 minutes and a standard deviation
balu736 [363]

Answer: 0.16

Step-by-step explanation:

Given that the run times provided are normally distributed ;

Mean(x) of distribution = 3 hours 50 minutes

Standard deviation(s) = 30 minutes

The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes

3 hours 20 minutes = (3 hrs 50 mins - 30 mins):

This is equivalent to :

[mean(x) - 1 standard deviation]

z 1 standard deviation within the mean = 0.84

z, 1 standard deviation outside the mean equals:

P(1 - z value , 1standard deviation within the mean)

1 - 0.8413 = 0.1587

= 0.16

7 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
uysha [10]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

Since h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

6 0
2 years ago
Determine the complement and/or supplement of each angle. If it is not possible, explain.
Alecsey [184]

Answer:

  • complement: 32.8°
  • supplement: 122.8°

Step-by-step explanation:

The sum of an angle A and its complement C is 90°:

  A + C = 90°

  C = 90° -A . . . . . subtract A from both sides.

That is, the complement of an angle is found by subtracting the angle from 90°.

__

The sum of an angle and its supplement is 180°. This means the supplement of an angle is found by subtracting the angle from 180°. You may notice the supplement is 90° more than the complement.

  A + S = 180°

  S = 180° -A = 90° +(90° -A)

__

For the given angle, the complement is ...

  C = 90° -57.2° = 32.8°

And the supplement is ...

  S = 180° -57.2° = 122.8°

_____

<em>Additional comment</em>

We generally like angle measures to be positive (as with all measures in geometry). Hence, we might say that the complement of an angle greater than 90° does not exist. YMMV

3 0
2 years ago
How do you round 3,915 o the nearest hundred?
s2008m [1.1K]
You uñere línea the niñez Andes circulé the One but 
8 0
3 years ago
Please help me please will give brainliest
Ksivusya [100]

Answer:

A. less than three batteries were used in five hours.

4 0
3 years ago
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