Answer: √(f^2 - 2f + 1) = a
Step-by-step explanation:
We have that:
f^2+g^4-2f+1 = a^2+(g^2)^2
And we want to find the value of a, so we should isolate it.
f^2 + g^4 - 2f + 1 = a^2 + g^(2*2) = a^2 + g^4
where i used that (x^y)^z = x^(y*z)
We can remove the term g^4 in both sides of the equation and get:
f^2 - 2f + 1 = a^2
now we can apply the square rooth to both sides and get
√(f^2 - 2f + 1) = a
So we just found the value of a.
Answer:
2
Step-by-step explanation:
The shape expanded in size by a factor of 2. So the dilation scale factor is 2
A b c and d r not answers, u need to tell how the different variations would change based on the numbers and where they r
A=-2;b=9;c=9;
delta=b^2-4*a*c
root1=(-b+(delta^(0.5)))/(2*a)
<span>root2=(-b-(delta^(0.5)))/(2*a)
delta =153
root1 = -0.8423
root2 =<span> 5.3423
Correct Answer is D</span></span>
Answer:
31.581 grams rounded to the nearest tenth is 31.6