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3 years ago

Find ST if S(-3, 10) and T(-2, 3).

Mathematics

1 answer:

8090 [49]3 years ago

4 0

Answer:

$ST = 5\sqrt{2}$

Step-by-step explanation:

Given:

S(-3, 10)

T(-2, 3)

Required:

SOLUTION:

Use the distance formula, $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ , to find ST.

Where,

$S(-3, 10) = (x_1, y_1)$

$T(-2, 3) = (x_2, y_2)$

$ST = \sqrt{(-2 -(-3))^2 + (3 - 10)^2}$

$ST = \sqrt{(1)^2 + (-7)^2}$

$= \sqrt{1 + 49}$

$= \sqrt{50} = \sqrt{25*2}$

$ST = 5\sqrt{2}$

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3 years ago

Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL

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In the triangle QNP, the sides can be calculate as following:

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It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

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