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Alinara [238K]
3 years ago
8

CAN I GET SOME HELP AND NOT SKIPPED?

Mathematics
2 answers:
Sliva [168]3 years ago
8 0

Answer:

The last one: 6.3 units.

Reptile [31]3 years ago
7 0

Answer: 6.3 units

Step-by-step explanation:

The formula for determining the distance between two points on a straight line is expressed as

Distance = √(x2 - x1)² + (y2 - y1)²

Where

x2 represents final value of x on the horizontal axis

x1 represents initial value of x on the horizontal axis.

y2 represents final value of y on the vertical axis.

y1 represents initial value of y on the vertical axis.

From the graph given,

x2 = 4

x1 = - 2

y2 = 4

y1 = 2

Therefore,

Distance = √(4 - - 2)² + (4 - 2)²

Distance = √6² + 2² = √36 + 4 = √40

Distance = 6.3 units

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Which expression uses the greatest common factor and the distributive property to rewrite the sum 75 + 45?
Vedmedyk [2.9K]
<span>75 + 45

First let's find the greatest common factor.
75: 1, 3, 5, 15, 25, 75
45: 1, 3, 5, 9, 15, 45
Their GCF is 15.

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To get 45, you multiply 15 by 3.

Therefore, 15(5 + 3) = 75 + 45.

</span><span>B. 15(5 + 3)
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7 0
3 years ago
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A beetle was running along a number line…
melamori03 [73]

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Its average speed is 7 units per second.

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4 0
3 years ago
If 2(4x + 3)/(x - 3)(x + 7) = a/x - 3 + b/x + 7, find the values of a and b.
zmey [24]

Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

2(4x+3)=a(x+7)+b(x-3)

As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

2(4\cdot -7+3)=a(-7+7)+b(-7-3)

2(-28+3)=a(0)+b(-10)

2(-25)=0-10b

-50=-10b

Divide both sides by -10:

\frac{-50}{-10}=b

5=b

Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

I notice that x-3 is 0 when x=3. So I'm going to replace x with 3.

2(4\cdot 3+3)=a(3+7)+b(3-3)

2(12+3)=a(10)+b(0)

2(15)=10a+0

30=10a

Divide both sides by 10:

\frac{30}{10}=a

3=a

So a=3 and b=5.

4 0
3 years ago
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