If the discriminant is negative no real solution exists. If the discriminant is equal to 0 only one real solution exists. If the discriminant is positive 2 real solutions exist. The discriminant: D = b² - 4 a c 1 ) - 7 x² + 6 x + 3 = 0 D = 6² - 4 · ( - 7 ) · 3 = 36 + 84 = 120 > 0 Answer: b) two solutions 2 ) - 8 x² - 8 x - 2 = 0 D = ( - 8 )² - 4 · ( - 8 ) · ( - 2 ) = 64 - 64 = 0 Answer: a ) one solution
