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Vilka [71]
3 years ago
5

Which inequality or inequalities have the same solution as 2 less than or equal too x + 3

Mathematics
2 answers:
RUDIKE [14]3 years ago
7 0
It will be x-3 still
kolbaska11 [484]3 years ago
5 0

Answer: Theres no unlike terms so the answer will still be x+3


Step-by-step explanation:

Theres no unlike terms so the answer will still be x+3

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I need help... how to simplify this ?
valentina_108 [34]

Answer:

b^{2} \sqrt{30b}

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

7 0
3 years ago
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The original price of a camera is $150. If a discount of 30% is given, what is the discounted price of the camera?
MArishka [77]
So, 30% is 0.30, but since you are taking off 30%, you are going to have 70% of the price which is 0.70. The word "of" lets you know that you are going to multiply. So, what you do is 150•0.70=105. The discounted price is $105
3 0
3 years ago
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1. You owe $2,348.62 on a credit card with an 8.75% APR. You pay $300.00 toward the card at the beginning of the month and anoth
satela [25.4K]
Part 1:

After payment of $300, remaining balance = $2,348.62 - $300 = $2,048.62.
Interest accrued is given by:

I=Prt \\  \\ =2,048.62\times0.0875\times \frac{1}{12}  \\  \\ =\$14.94

Had it been $600 was paid, remaining balance = $2,348.62 - $600 = $1748.62. Interest accrued is given by:

I=1,748.62\times0.0875\times \frac{1}{12}  \\  \\ =$12.75

Difference in interest accrued = $14.94 - $12.75 = $2.19


Part 2:

The present value of an annuity is given by:

PV= \frac{P\left[1-\left(1+ \frac{r}{12} \right)^{-12n}\right]}{ \frac{r}{12} }

Where PV is the amount to be repaid, P is the equal monthly payment, r is the annual interest rate and n is the number of years.

Thus,

2348.62= \frac{600\left[1-\left(1+ \frac{0.0875}{12}\right)^{-12n}\right]}{\frac{0.0875}{12}}  \\  \\ \Rightarrow 1-(1+0.007292)^{-12n}= \frac{2348.62\times0.0875}{12\times600} =0.028542 \\  \\ \Rightarrow(1.007292)^{-12n}=1-0.028542=0.971458 \\  \\ \Rightarrow \log(1.007292)^{-12n}=\log0.971458 \\  \\ \Rightarrow-12n\log1.007292=\log0.971458 \\  \\ \Rightarrow-12n= \frac{\log0.971458}{\log1.007292} =-3.985559 \\  \\ \Rightarrow n= \frac{-3.985559}{-12} =0.332130

Therefore, the number of months it will take to pay of the debt is 3.99 months which is approximately 4 months.
6 0
3 years ago
Read 2 more answers
Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
3 years ago
You deposit $2000 into a savings account to pay 5% interest compounded annually if you make no more deposit or any withdrawal is
Bond [772]

Answer: A = 2000(1.05)^5

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $2000

r = 5% = 5/100 = 0.05

n = 1 because it was compounded once in a year.

t = 5 years

Therefore, the equation that shows how much money will be in the account after five years is

A = 2000(1 + 0.05/1)^1 × 5

A = 2000(1.05)^5

5 0
3 years ago
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