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ipn [44]
3 years ago
7

GEOMETRY HELP PLEASE!!!!!!!!!!!

Mathematics
1 answer:
Setler [38]3 years ago
8 0
I have the same problem. if i find the answer i will give it to you

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The slope of a line is 2. The y-intercept of the line is –6. Which statements accurately describe how to graph the function?
garik1379 [7]

Answer:

a

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which inequality matches the given situation if w represents weight in pounds:Baby tigers can be no larger than 4 pounds.
ozzi

Given:

w be the weight in pounds of a baby tigers.

To find:

The inequality if baby tigers can be no larger than 4 pounds.

Solution:

Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.

Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

w\leq 4

Therefore, the required inequality is w\leq 4.

4 0
3 years ago
The following equation defines f(x)=-3x-5 . If (-5,n) is an ordered pair of the function rule, what is the value of n?
ElenaW [278]

Given:

The function is

f(x)=-3x-5

(-5,n) is an ordered pair of the function rule.

To find:

The value of n.

Solution:

If (-5,n) is an ordered pair of the function rule, then the function must be satisfied by the point (-5,n). It means f(-5)=n.

Substitute x=-5 in the given function.

f(-5)=-3(-5)-5

f(-5)=15-5

f(-5)=10

We know that, f(-5)=n. So,

n=10

Therefore, the value of n is 10.

4 0
3 years ago
If snickers are sold in pack of 6 and kit Kats are sold in packs of 15 how many packs do you need to buy to have a equal amount
iragen [17]

Answer: 5 packs of Snickers and 2 packs of Kit Kats.


Step-by-step explanation: How? Okay so snickers come in packs of 6 to find the number that will be equal to Kit Kats you must figure out factors. 30 has a factor of 6 and 15. 5 packs of snickers will get you 30 total snickers. 2 packs of Kit Kats will get you a total of 30 Kit Kats. I hope this helped! (:


3 0
3 years ago
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

Given equation of circle is,

{x}^{2}  +  {y}^{2}  - 6y - 12 = 0 \\ by \: compairing \: it \: with \:   \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f=  - 6 \\ or \: f=  - 3 \\ c =  - 12

again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0
3 years ago
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