This is the correct work, but your answer should be written as 5x/2.
Answer:
(h+4)
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
For any point (x, y ) on the parabola the focus and directrix are equidistant
Using the distance formula
= | y - 8 |
Squaring both sides gives
(x - 2)² + (y - 4)² = (y - 8)²
(x - 2)² + y² - 8y + 16 = y² - 16y + 64 ( rearrange and simplify )
(x - 2)² = - 8y + 48
8y = - (x - 2)² + 48
y = - 
(x - 2)² + 6 → A
Answer:
246 ft is the maximum height
Step-by-step explanation:
The height h given above is a quadratic function. The graph of h as a function of time t gives a parabolic shape and the maximum height h occur at the vertex of the parabola. For a quadratic function of the form h = a t² + bt + c, the vertex is located at t = - b / 2a. Hence for h given above the vertex in the question s(t) = 124 + 64t − 16t², is at t
t = -64/2(-16) = 64/32 = 2 seconds
Thus, 2 seconds after the object was thrown, it reaches its highest point (maximum value of h) which is given by
h = -16(2)² + 64 (2) + 124 = 246eet
Area=width*height
area=(11.7)*(15.4)
area=180.18cm^2
