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Delvig [45]
3 years ago
5

What are the multiples of 3 and 4 between 1 and 30

Mathematics
1 answer:
mafiozo [28]3 years ago
3 0

Answer: 3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4: 4, 8, 12, 16, 20, 24, 28

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94.2 cm ^2

Step-by-step explanation:

Pie= 3.14

3.15 x 5 x 6= 94.2

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Y=4x. Y=40. What does x equal
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Answer:

Your answer is 10!

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Which of the following addition problems yields a sum that is an irrational number? Select TWO that apply. 23+97 2√+2√ 32+25√ 4√
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3 years ago
I was at the store, and saw two sizes of avocados being sold. The regular size sold for $0.84 each. For what prices would the la
JulsSmile [24]

Answer:

The bigger avocado will be a better deal if the ratio of the sizes of the bigger one to the smaller one is less than the ratio of the prices of the bigger one to the smaller one.

Step-by-step explanation:

Given that two sizea of avocados are being sold, since the regular size is being sold for $0.84 each, let the price for the bigger avocado be $x.

Then note the following:

1. How bigger than the smaller avocado is the bigger one?

This would determine if the price for the bigger one is a bargain, or a mistake.

If for instance, the bigger avocado is double the size of the smaller one, then for any price, $x less that $1.68 (twice of $0.84), it is a bargain.

The bigger avocado will be a better deal if the ratio of the sizes bigger one to the smaller one is less than the ratio of the prices of the bigger one to the smaller one.

6 0
3 years ago
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You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
navik [9.2K]

Answer:

1) yes ; 2) 1/36 ; 3) 1/36 ; 4) 1/18

Step-by-step explanation:

Given the following :

Two fair dice : 1 green ; 1 red

A) Are the outcomes on the dice independent:

Yes, becomes the outcome of the green dice does not have any effect on the outcome of the red dice.

B) Find P(1 on green die and 5 on red die).

Probability = (number of required outcome) / (total possible outcomes)

Total outcomes of a dice = 6

P(1 on green) = 1 / 6

P(5 on red) = 1/6

P(1 on green die and 5 on red die) :

(1/ 6) × (1/6) = 1/36

C) Find P(5 on green die and 1 on red die)

P(5 on green) = 1/6

P(1 on red) = 1/6

Find P(5 on green die and 1 on red die):

1/6 × 1/6 = 1/36

D) Find P((1 on green die and 5 on red die) or (5 on green die and 1 on red die))

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P(1 on green die and 5 on red die) = 1/36

P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) =

P(5 on green die and 1 on red die) + P(1 on green die and 5 on red die)

= (1/36 + 1/36) = 2 /36 = 1/18

8 0
3 years ago
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