The dimensions of fields are length = 264 yards and width = 66 yards
<em><u>Solution:</u></em>
Given that rectangular field is five times as long as it is wide and perimeter of field is 660 yards
Let "L" be the length of rectangular field
Let "W" be the width of rectangular field
From given information,
Length = 4 times the width
L = 4W
<em><u>The perimeter of rectangle is given as:</u></em>
perimeter of rectangle = 2(length + width)
Substituting the given values in above formula,
660 = 2(4W + W)
330 = 5W
<h3>W = 66</h3>
Then length is given as: L = 4W
L = 4(66) = 264
<h3>L = 264</h3>
Thus the dimensions of fields are length = 264 yards and width = 66 yards