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kondaur [170]
3 years ago
7

The rectangular field is five times as long as it is wide. If the perimeter of the field is 660 yards, what are fields dimension

s?
Mathematics
1 answer:
never [62]3 years ago
7 0

The dimensions of fields are length = 264 yards and width = 66 yards

<em><u>Solution:</u></em>

Given that rectangular field is five times as long as it is wide and perimeter of field is 660 yards

Let "L" be the length of rectangular field

Let "W" be the width of rectangular field

From given information,

Length = 4 times the width

L = 4 \times W

L = 4W

<em><u>The perimeter of rectangle is given as:</u></em>

perimeter of rectangle = 2(length + width)

Substituting the given values in above formula,

660 = 2(4W + W)

330 = 5W

<h3>W = 66</h3>

Then length is given as: L = 4W

L = 4(66) = 264

<h3>L = 264</h3>

Thus the dimensions of fields are length = 264 yards and width = 66 yards

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3 0
2 years ago
Sam has 100 feet of fencing. Does he have enough fencing to enclose a circular region whose area is 630 square feet? Show work!
slavikrds [6]
A=pi(radius^2)
630/3.14=200.64
radius=14.16 feet
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6 0
4 years ago
3x-13=74 solve for x
never [62]

Answer:

x=29

Step-by-step explanation:

3x-13=74

We want to solve for x, so we need to isolate it.

The first step is to add 13 to each side.

3x-13+13=74+13

3x = 87

Then we divide by 3 on each side

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7 0
3 years ago
The mean of this data set is 9. What number is missing?<br><br> 11,20,_,3,1
kherson [118]
Let the missing number be x

Mean is the total sum of data over the number of data therefore,

(11+20+x+3+1) / 5 = 9
Then simplify
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Then multiply 5 to both sides
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Then subtract 35 to both sides to find x
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Hope this helps!

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2 years ago
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