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kondaur [170]
2 years ago
7

The rectangular field is five times as long as it is wide. If the perimeter of the field is 660 yards, what are fields dimension

s?
Mathematics
1 answer:
never [62]2 years ago
7 0

The dimensions of fields are length = 264 yards and width = 66 yards

<em><u>Solution:</u></em>

Given that rectangular field is five times as long as it is wide and perimeter of field is 660 yards

Let "L" be the length of rectangular field

Let "W" be the width of rectangular field

From given information,

Length = 4 times the width

L = 4 \times W

L = 4W

<em><u>The perimeter of rectangle is given as:</u></em>

perimeter of rectangle = 2(length + width)

Substituting the given values in above formula,

660 = 2(4W + W)

330 = 5W

<h3>W = 66</h3>

Then length is given as: L = 4W

L = 4(66) = 264

<h3>L = 264</h3>

Thus the dimensions of fields are length = 264 yards and width = 66 yards

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Crazy boy [7]

Hello from MrBillDoesMath!

Answer:

4/sin(80)

which is approximately 4.06



Discussion:

From the triangle, not drawn too accurately  (see attachment)


sin(80) = side opposite /hypotenuse   =>

sin (80) =  4/c            =>       multiply both sides by "c"

c sin(80) = 4/c * c      =>      

c sin(80) = 4               =>      divide both sides by sin(80)

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and 4/sin(80) is approximately 4.06


Thank you,

MrB

6 0
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