Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:
We substitute x=161.4 , 
, and 
to get:
From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
B
Step-by-step explanation:
Because yes
Answer:
mp=2800
mp=cp+40%ofcp=cp+40/100×cp=1.4cp
2800=1.4çp
cp=2800/1.4=2000
discount=20%
profit%=?
Step-by-step explanation:
sp=mp-discount%of mp=2800-20/100×2800=2240
profit=sp-cp=2240-2000=240
profit%=profit/cp×100%=240/2000×100%=12%
Answer: No, it is not a solution
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Explanation:
The point (3,-4) means that x = 3 and y = -4 pair up together
Let's plug these x,y values into each equation
Starting with the first equation, we get,
y = 4x-16
-4 = 4(3)-16 ... x replaced with 3; y replaced with -4
-4 = 12-16
-4 = -4 .... this is a true statement
Repeat for the second equation
y = 2x-6
-4 = 2(3)-6
-4 = 6-6
-4 = 0 ... this is false
Since we get a false statement, this means (3,-4) is not on the line y = 2x-6, which means that overall (3,-4) is not a solution to the system of equations. The point (3,-4) must make both equations true for it to be a solution.
Answer: its b
Step-by-step explanation:
