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4 years ago

What is the coefficient of the variable in the expression 6 − 4x − 8 + 2

Mathematics

2 answers:

g100num [7]4 years ago

7 0

Answer:

-4

Step-by-step explanation:

6 − 4x − 8 + 2

The variable is x

The coefficient is the number in front of the variable ( it will include the sign)

-4 is the coefficient

Akimi4 [234]4 years ago

6 0

Answer:

-4

Step-by-step explanation:

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The length of a rectangle is 3x^2+7x+9 and it’s width is 3x+6

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Answer: 5x/9 + 10 Associative Pr

operty of addition

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4 years ago

a truck costing 25000 with a residual value of 5000. the truck's estimated life is 10 years. what is the book value at the end o

sineoko [7]

$25,000 - 5,000 = $20,000
Since the useful life is 10 years or 10% per year, double-declining rate would be 20%

Year 1
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3 0

4 years ago

I keep putting in the formula but I keep getting the answer wrong

Advocard [28]

Answer:

314 in² (nearest whole number)

Step-by-step explanation:

Radius of a regular polygon: The distance from the center of the polygon to any vertex. The radius of a hexagon is equal to the length of one side.

Therefore, from inspection of the given diagram:

radius = 11 in ⇒ side length = 11 in

To find the area of a regular polygon, we first need to calculate the apothem. The apothem is the line drawn from the center of the polygon to the midpoint of one of its sides.

$\textsf{Length of apothem (a)}=\dfrac{s}{2 \tan\left(\frac{180^{\circ}}{n}\right)}$

where:

s = length of one side
n = number of sides

Given:

s = 11 in
n = 6

Substitute the given values into the formula and solve for a:

$\implies \textsf{a}=\dfrac{11}{2 \tan\left(\frac{180^{\circ}}{6}\right)}=\dfrac{11\sqrt{3}}{2}$

Area of a Regular Polygon

$\textsf{A}=\dfrac{n\:s\:a}{2}$

where:

n = number of sides
s = length of one side
a = apothem

Given:

n = 6
s = 11

$\textsf{a}=\dfrac{11\sqrt{3}}{2}$

Substitute the given values into the formula and solve for A:

$\implies \sf A=\dfrac{6 \cdot 11 \cdot \dfrac{11\sqrt{3}}{2}}{2}$

$\implies \sf A=314.3672216...$

$\implies \sf A=314\:\:in^2\:\:(nearest\:whole\:number)$

8 0

2 years ago

The product of 9 and a number n

MAXImum [283]

Answer:

My answer to the question is 9×n=9n.

7 0

4 years ago

On #10 i need help to solve this. please and thank you.

valina [46]

10a. $f(x) = x - 4$
 $h(x) = \sqrt{x - 5}$
 $(f - h)(6) = (6 - 4) - (\sqrt{6 - 5})$
 $(f - h)(6) = 2 - \sqrt{1}$
 $(f - h)(6) = 2 - 1$
 $(f - h)(6) = 1$

10b. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $(f * g)(x) = (x - 4)(\frac{1}{x - 3})$
 $(f * g)(x) = \frac{x - 4}{x - 3}$
 Domain: (-∞, 3) ∨ (3, ∞) {x|x ≠ 3}
 Interval Notation: (3 < x < 3), (3 > x > 3)

10c. $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt{x - 5}$
 $(g * h)(x) = (\frac{1}{x - 3})(\sqrt{x - 5})$
 $(g * h)(x) = \frac{\sqrt{x - 5}}{x - 3}$

10d. $f(x) = x - 4$
 $g(x) = \frac{1}{x - 3}$
 $h(x) = \sqrt[3]{x - 7}$
 $h(x) = (f * g)(x)$
 $\sqrt[3]{x - 7} = (x - 4)(\frac{1}{x - 3})$
 $\sqrt[3]{x - 7} = \frac{x - 4}{x - 3}$
 $(\sqrt[3]{x - 7})^{3} = (\frac{x - 4}{x - 3})^{3}$
 $x - 7 = \frac{(x - 4)^{3}}{(x - 3)^{3}}$
 $(x - 3)^{3}(x - 7) = (x - 4)^{3}$
 $(x^{3} - 9x^2 + 27x + 27)(x - 7) = (x^{3} - 12x^{2} + 48x - 64)$
 $x^{4} - 16x^{3} + 90x^{2} - 216x + 189 = x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 90x^{2} - 216x + 189 = 17x^{3} - 12x^{2} + 48x - 64$
 $x^{4} + 102x^{2} - 216x + 189 = 17x^{3} + 48x - 64$
 $x^{4} + 102x^{2} + 189 = 17x^{3} + 264x - 64$
 $x^{4} + 102x^{2} + 253 = 17x^{3} + 264x$
 $x^{4} - 17x^{3} + 102x^{2} - 264x + 253 = 0$
 $x = 4\ or\ 8$

4 0

3 years ago