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vlabodo [156]
3 years ago
8

99 points on the line please I really need help with these four questions. Please don't just put random stuff I will report you.

thank you for the help :)

Physics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

1. Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.

2. Below the tectonic plate is a magma chamber that is shooting up mafic magma. As it emerges, it creates an island. The plate that the magma is puncturing is also happening to be moving, so it makes one island, and it floats on. Think of it as a chimney. It blows a puff of smoke, the wind blows it away. Then another puff emerges, and so on. Those other islands no longer sit on the source of the volcano.

3. Metamorphism occurs when there is enough pressure and heat in order to rearrange the structures of each mineral into a new mineral. Contact metamorphism occurs when lava shoots through and touches other rocks, which heats them up and driving metamorphism. In contact, there is no pressure. In regional, there is a large area of both heat and pressure being applied on the rocks.

bearhunter [10]3 years ago
6 0
<span>1. Each station can detect how far away the epicenter was. So each station basically has a circle made of possible epicenters. When you have three, you narrow it down to one, final point.

2. Below the tectonic plate is a magma chamber that is shooting up mafic magma. As it emerges, it creates an island. The plate that the magma is puncturing is also happening to be moving, so it makes one island, and it floats on. Think of it as a chimney. It blows a puff of smoke, the wind blows it away. Then another puff emerges, and so on. Those other islands no longer sit on the source of the volcano.

3. Metamorphism occurs when there is enough pressure and heat in order to rearrange the structures of each mineral into a new mineral. Contact metamorphism occurs when lava shoots through and touches other rocks, which heats them up and driving metamorphism. In contact, there is no pressure. In regional, there is a large area of both heat and pressure being applied on the rocks. </span>
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What is mass ?<br> Please help
givi [52]

Answer:

Gage's definition: a measure of the amount of matter in an object.

Explanation:

Dictionary definition: a coherent, typically large body of matter with no definite shape.

Thanks for letting me help!!

4 0
4 years ago
Read 2 more answers
Calculate the wavelength of the electromagnetic radiation whose frequency is 7.5 x 10^12 Hz
tamaranim1 [39]

velocity of electromagnetic waves=3.0×10^8.

wavelength=velocity/frequency

(3.0×10^8)/(7.5×10^12)

=0.00004

4 0
4 years ago
An object with a mass of 78kg is lifted through a height of 6 meters. How much work is done?
g100num [7]
Work = force x distance. 

force = mass x acceleration 

work = mass x acceleration x diastance 

use acceleration of gravity in this problem 

W (J) = m (kg) x a (m/s/s) x d (m) 
W = 78 x 9.8 x 6 
W = 4586.4

3 0
3 years ago
If the coefficient of kinetic friction between a 22 kg kg crate and the floor is 0.27, what horizontal force is required to move
alina1380 [7]

Answer:

58.27 N

Explanation:

the data we have is:

mass: m=22kg

coefficient of friction: \mu =0.27

and we also know the acceleration of gravity is g=9.81m/s^2

We need to do an analysis of horizontal and vertical forces acting on the object:

-------

Vertically the forces acting on the object:

  • Normal force N (acting up from the object)
  • weight: w=mg (acting down from)

so the sum of forces in the vertical axis "y" are:

F_{y}=N-w\\F_{y}=N-mg

from Newton's second Law we know that F=ma, so:

ma_{y}=N-mg

and since the object is not accelerating in the vertical direction (the movement is only horizontal) a_{y}=0, and:

0=N-mg\\N=mg

-----------

now let's analyze the horizontal forces

  • frictional force: f= \mu N and since N=mg  --> f=\mu mg
  • force to move the object: F

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

F=ma_{x}=F-f\\ma_{x}=F-\mu mg

and we are told that the crate moves at a steady speed, thus there is no acceleration: a_{x}=0

and we get:

0=F-\mu mg\\F=\mu mg

substituting known values:

F=(0.27)(22kg)(9.81m/s^2)\\F=58.27N

3 0
3 years ago
Two wires are made from the same material. One wire has a resistance of 0.10 ω. The other wire is twice as long as the first wir
Anna71 [15]

Answer:

Explanation:

Given that,

First wire has a resistance of

R1 = 0.1 Ω

We are told that

Second wire is twice as long as the first wire.

Then,

Let the first wire has length

L1 = x

Then, second wire will have

L2 = 2x

Also, the radius of the second wire is half the radius of the first wire

Let the first wire has radius

r1 = y

Then, it area is

A1 = πr1² = πy²

Then, the second wire has radius

r2 = ½y

It area is also

A2 = πr2² = π(½y)² = ½πy²

Since the wire is made of the same material, then, they will have the same resistivity ρ

Then, we want to find the resistance of the second wire

Using

R = ρL/A

Where

R = resistance

ρ = sensitivity

L = length

A = area

Then, make resistivity subject of formula since it is a constant

RA = ρL

Then, ρ = RA/L

Then,

R1 • A1 / L1 = R2 • A2 / L2

Substituting each value

0.1 × πy² / x = R2 × ¼πy² / 2x

Cross multiply

0.1 × πy² × 2x = R2 ×¼π y² × x

Then,

R2 = 0.1 × πy² × 2x / ¼πy² × x

R2 = 0.1 × 2 / ¼

R2 = 0.8Ω

The resistance of the second wire is 0.8Ω

6 0
4 years ago
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