Answer:
hmax = 1/2 · v²/g
Explanation:
Hi there!
Due to the conservation of energy and since there is no dissipative force (like friction) all the kinetic energy (KE) of the ball has to be converted into gravitational potential energy (PE) when the ball comes to stop.
KE = PE
Where KE is the initial kinetic energy and PE is the final potential energy.
The kinetic energy of the ball is calculated as follows:
KE = 1/2 · m · v²
Where:
m = mass of the ball
v = velocity.
The potential energy is calculated as follows:
PE = m · g · h
Where:
m = mass of the ball.
g = acceleration due to gravity (known value: 9.81 m/s²).
h = height.
At the maximum height, the potential energy is equal to the initial kinetic energy because the energy is conserved, i.e, all the kinetic energy was converted into potential energy (there was no energy dissipation as heat because there was no friction). Then:
PE = KE
m · g · hmax = 1/2 · m · v²
Solving for hmax:
hmax = 1/2 · v² / g
For this problem, we would be using the formula: Vf^2 = Vi^2 + 2ad
where:
Vf = 400m/s
Vi = 300m/s
a = ?
d = 4.0km
= 4000m
400^2 = 300^2 + 2a4000
a = [ 160000 - 90000 ] / 8000
a = 8.75m/s^2
rounding it off to 2 significant figures, will give us 8.8 m/s^2.
Answer:
The first answer is W and Z, since they appear to be a period apart. Dont know the second question. I did what I could, hope someone can answer the second.
Answer:
Explanation:
We shall represent each displacement in vector form .
i will represent east , j will represent north .
D₁ = 4.1 west = - 4.1 i
D₂ = 17.3 north = 17.3 j
D₃ = - 1.2 cos65.4 i + 1.2 sin65.4 j
= - .5 i + 1.09 j
Total displacement
= D₁ + D₂ + D₃
= - 4.1 i + 17.3 j - .5 i + 1.09 j
D = - 4.6 i + 18.39 j
magnitude of D
= √ ( 4.6² + 18.39² )
= √ (21.16 + 338.2 )
= √359.36
= 18.95 km .
Final displacement = 18.95 km .
Answer:
please write the question by our way which we can understand
