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3 years ago

For the sequence 3,9,27,81…, give a formula for its nth term:

Mathematics

1 answer:

stellarik [79]3 years ago

5 0

That would be 3 to the nth power—>3^n

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Can help me with this question please

andrey2020 [161]

Machine A:

60 / 10 = 6 - 10 minute segments per hour

7 x 6 = 42 - parts per hour

42 x 12 = 504 - parts made on Monday

Machine B:

60 / 15 = 4 - 15 minute segments per hour

16 x 4 = 64 - parts per hour

64 x 10 = 640 - parts made on Monday

504 + 640 = 1144 - parts made by the two machines on Monday

Hope this helps!! :)

5 0

3 years ago

ILL MARK BRAINLIEST, PLZ HELP ME ASAP!!!!!!!!!!

siniylev [52]

The answer is left 4 and right 3 units hope this helps

7 0

3 years ago

I am using Bay County, a county located in the state of Michigan. According to the U.S. Census Bay county had a population of 10

xeze [42]

Given:

The intial population in 2019 is, P₀ = 103126.

The final population in 2020 is, P = 103856.

The objective is to find the population in the year 2039.

Explanation:

The general exponential form of population growth is,

$P=P_0\times e^{rt}\text{ . . . . . . . (1)}$

Here, t represents the time period.

To find t:

The value of <em>t</em> from 2019 to 2020 can be calculated as,

$\begin{gathered} t=2020-2019 \\ t=1 \end{gathered}$

To find r :

On plugging the obtained values in equation (1),

$\begin{gathered} 103856=103126\times e^{r(1)} \\ \frac{103856}{103126}=e^{r(1)} \\ \log (\frac{103856}{103126})=r \\ r=0.003 \end{gathered}$

To find population at 2039:

The time period <em>t</em> can be calculated as,

$\begin{gathered} t=2039-2019 \\ t=20\text{ years} \end{gathered}$

Now, final population after 2019 can be calculated as,

$undefined$

4 0

2 years ago

Us the expression (8x + 2) + (- 9x + 7)

malfutka [58]

Answer:

8x2=16 9x7=63

63+16=79

Step-by-step explanation:

7 0

3 years ago

Use doubles minus one to slove 8+7

bearhunter [10]

I got 30 as an answer

8 0

3 years ago