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navik [9.2K]
3 years ago
8

Use doubles minus one to slove 8+7

Mathematics
1 answer:
bearhunter [10]3 years ago
8 0
I got 30 as an answer
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Circle P is representing by the equation (x - 2)^2 + (y + 2)^2 = 9.
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Circle with the radius 3 (r=3) and the center (2, -2)
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What is the value of z in the equation 11 + z = 6?<br><br> 66<br> 5<br> −5<br> 1
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-5 will be your answer. Hope this helps!
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F(x) = -7x^2+8x+2 what is the value of the discriminant of f
Murrr4er [49]

Answer:

D = 120,    there are 2 real roots for F(x)

Step-by-step explanatU

using the

formula  D = b^2 - 4ac  for discriminant

D =  8^2  - 4*(-7)*2

D = 64  + 56  =  120

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The populations of two cities after t years can be modeled by -150t+50,000 and 50t+70,0000 . What is the difference in the popul
Sindrei [870]

Answer:

25,800

Step-by-step explanation:

Plug in 4 everytime you see T.

multiple-150 times 4 plus 50000 which gives you 49,400.

then multiple 50 times 4 and add 75000, giving you 75,200 then subtract 75,200 - 49,400 which you end up with 25,800.

hope this helped

5 0
2 years ago
A local company is concerned about the number of days missed by its employees due to ill ness. A Random Sample of 10 employees i
sukhopar [10]

Answer:

The incentive program does not cuts down on the number of days missed by employees.

Step-by-step explanation:

The dependent t-test (also known as the paired t-test or paired samples t-test) compares the two means associated groups to conclude if there is a statistically significant difference amid these two means.

A paired <em>t</em>-test would be used to determine whether the incentive program cuts down on the number of days missed by employees.

The hypothesis for the test can be defined as follows:

<em>H₀</em>: The incentive program does not cuts down on the number of days missed by employees, i.e. <em>d</em> ≥ 0.

<em>Hₐ</em>: The incentive program cuts down on the number of days missed by employees, i.e. <em>d</em> < 0.

From the information provided the data computed is as follows:

 n=10\\\bar d=-1.1\\SD_{d}=2.99

Compute the test statistic value as follows:

 t=\frac{\bar d}{SD_{d}/\sqrt{n}}

   =\frac{-1.1}{2.99/\sqrt{10}}\\\\=-1.16

The test statistic value is -1.16.

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.

Compute the p-value of the test as follows:

p-value=P(t_{n-1}

*Use a t-table.

The p-value of the test is 0.1379.

The p-value of the test is very large for all the commonly used significance level. The null hypothesis will not be rejected.

Thus, there is not enough evidence to support the claim.

Conclusion:

The incentive program does not cuts down on the number of days missed by employees

4 0
3 years ago
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