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3 years ago

68.75 rounded to the nearest tenths

Mathematics

2 answers:

pashok25 [27]3 years ago

8 0

Answer:

The answer would be 16.8

Step-by-step explanation:

This is because you round up a number is the decimal to the right of it is greater than or equal to 5

katrin [286]3 years ago

6 0

Answer:

68.6 to the nearest tenth.

Step-by-step explanation:

That would be 68.8 because the hundredth's digit is 5. We add 1 the tenth's digit : 7 + 1 = 8.

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The median of 15, 17, 13, 19, 20, 33, 22, 12, 18, and ◼ is 18.5. Is it possible to determine the missing value?

yanalaym [24]

It is NOT possible to determine the missing value from the given data.

<h3>Mean and Median</h3>

Mean is the average of a number of data while the median is the number at the middle of the given data.

For a given data with a missing value, we can only find the missing value by calculating the mean of the data and equating the given mean.

Hence from the given data, it is NOT possible to determine the missing value from the given data.

Learn more on median and mean here; brainly.com/question/14805451

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3 years ago

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What is the range of the given function?<br><br> {(–2, 0), (–4, –3), (2, –9), (0, 5), (–5, 7)}

Novay_Z [31]

Range is the set of possible output values of a function. In this case, it’s (-9, -3, 0, 5, 7).

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3 years ago

Which expression represents 4 more than 2 times the value of n?

Bogdan [553]

2n+4
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3 years ago

Rewrite (2x^2+13x+26) / x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x). In the rewritten expression, q(x) is_____and r

likoan [24]

The value of q(x) is $2 x+5$

The value of r(x) is $6$

Explanation:

The given expression is $\frac{2 x^{2}+13 x+26}{x+4}$

We need to rewrite the expression in the form of $q(x)+\frac{r(x)}{b(x)}$

Simplifying the expression, we get,

$\frac{2 x^{2}+8 x+5x+26}{x+4}$

Separating the fractions, we have,

$\frac{2 x^{2}+8 x}{x+4}+\frac{5 x+26}{x+4}$

$2 x+\frac{5 x+26}{x+4}$ -----------(1)

Now, we shall further simplify the term $\frac{5 x+26}{x+4}$ , we get,

$\frac{5 x+26}{x+4}=\frac{5 x+20}{x+4}+\frac{6}{x+4}$

Common out 5 from the numerator, we have,

$\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$

Substituting the value $\frac{5 x+26}{x+4}=5+\frac{6}{x+4}$ in the equation(1), we get,

$2 x+5+\frac{6}{x+1}$

Thus, the expression $\frac{2 x^{2}+13 x+26}{x+4}=2 x+5+\frac{6}{x+1}$ is in the form of $q(x)+\frac{r(x)}{b(x)}$

Hence, we have,

$q(x)=2 x+5$

$r(x)=6$ and

$b(x)=x+4$

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3 years ago

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kobusy [5.1K]

Answer:

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Step-by-step explanation:

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3 years ago

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