In this problem, you apply principles in trigonometry. Since it is not mentioned, you will not assume that the triangle is a special triangle such as the right triangle. Hence, you cannot use Pythagorean formulas. The only equations you can use is the Law of Sines and Law of Cosines.
For finding side a, you can answer this easily by the Law of Cosines. The equation is
a2=b2 +c2 -2bccosA
a2 = 11^2 + 8^2 -2(11)(8)(cos54)
a2 = 81.55
a = √81.55
a = 9
Then, we use the Law of Sines to find angles B and C. The formula would be
a/sinA = b/sinB = c/sinC
9/sin54° = 11/sinB
B = 80.4°
9/sin54° = 8/sinC
C = 45.6°
The answer would be: a ≈ 9, C ≈ 45.6, B ≈ 80.4
Please mark me brainiest i think the answer is 2.600
Answer:
I NEED HELP WITH THIS ONE TO
Step-by-step explanation:
2 , 6 , 17 , 47 , <u>108</u> , ...
t(n) = 2n^3 - 8.5n^2 + 15.5n - 7
In the ordered pair (2, 12), x = 2 and y = 12.
Substitute these values into each inequality to see if the resulting inequality is true.
y > 2x + 4
12 > 2(2) + 4 Twelve is greater than 2 times 2 plus 4 ...hmmm
12 > 4 + 4
12 > 8 Twelve is greater than 8 ....this is TRUE...go to the next inequality
y < 3x + 7
12 < 3(2) + 7 Twelve is less than 3 times 2 plus 7 ...interesting
12 < 6 + 7
12 < 13 Twelve is less than 13 ... this is TRUE also
Therefore; the answer is b. Yes
It must create a true inequality for BOTH inequalities in order for the ordered pair to be a solution
