1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
defon
3 years ago
10

Problem 7-35 A satellite range prediction error has the standard normal distribution with mean 0 NM and standard deviation 1 NM.

Find the following probabilities for the prediction error: (a) less than 1.33 NM
Mathematics
1 answer:
kozerog [31]3 years ago
7 0

Answer:

0.9082 is the probability that the prediction error is less than 1.33 NM

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0 NM

Standard Deviation, σ = 1 NM

We are given that the distribution of prediction error is a bell shaped distribution that is a standard normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(less than 1.33 NM)

P( x < 1.33) = P( z < \displaystyle\frac{1.33 - 0}{1}) = P(z < 1.33)

Calculation the value from standard normal z table, we have,  

P(x < 1.33) =0.9082= 90.82\%

0.9082 is the probability that the prediction error is less than 1.33 NM

You might be interested in
P(5,6), -4x + 5y = 15 <br> into slope intercept form
Vaselesa [24]

Answer:

y = 4/5x - 3

Step-by-step explanation:

The slope-intercept form of a line is y = mx + b. We need to isolate the y.

(add 4x to 15)

-4x + 5y = 15

5y = 4x + 15

(divide by 5 from both sides)

y = 4/5x + 15/5

y = 4/5x + 3

8 0
3 years ago
Find the missing number of each unit rate. 155 = ?1 246 = ?1<br><br>worth 15 points!!!
alexgriva [62]

This is an incomplete question, the correct question is given below.

Find the missing number of each unit rate \frac{15}{5}=\frac{?}{1} and \frac{24}{6}=\frac{?}{1}

Answer : The missing number of each unit rate of \frac{15}{5}=\frac{?}{1} and \frac{24}{6}=\frac{?}{1} are, 3 and 4 respectively.

Step-by-step explanation :

As we know that a unit rate is a rate in which 1 is present in denominator.

Or we can say that,

A unit rate is also called a single unit rate that means it will compare 1 unit of some quantity to a different units of a different quantity.

As we are given that that unit rates:

\frac{15}{5}=\frac{?}{1} and \frac{24}{6}=\frac{?}{1}

Now we have to determine the missing number of each unit rates.

So, we can write the given expression as:

\frac{15}{5}=\frac{?}{1}

When are dividing 15 by 5, we get:

\frac{15}{5}=\frac{3}{1}

Thus, the missing number is, 3

And

\frac{24}{6}=\frac{?}{1}

When are dividing 24 by 6, we get:

\frac{24}{6}=\frac{4}{1}

Thus, the missing number is, 4

7 0
3 years ago
9*7/2*6*1-3*876+12,557,000
Aleksandr [31]
Answer is 12,554,561
8 0
3 years ago
Albert mixes 10 grams of 15% sugar and 25 grams of 10% sugar syrup. How many grams of sugar does the mixture contain.
FromTheMoon [43]
I think the answer is 35 grams but it might be something else
4 0
3 years ago
Read 2 more answers
Is -2/3x - 2 equivalent to -2/3x + (-2)?
adell [148]

Answer: Yes

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Other questions:
  • Which equations and/or functions represent the graphed line? Check all that apply.
    11·2 answers
  • In Exercise, sketch the graph of the function.<br> f(x) = 5x– 2
    9·1 answer
  • Can somebody solve this for me? thank you
    13·1 answer
  • A Train travels at a constant rate of 45 miles per hour. What is the distance,d,in miles,that the train travels in (t) hours ?
    10·1 answer
  • My life is on the LINE help me!
    6·2 answers
  • Whats 2x2x2x2x2x2x2x2x2x2x2x2x2
    13·1 answer
  • Determine whether the linear transformation T is invertible by considering its matrix with respect to the standard bases.
    8·1 answer
  • How do I do this question?
    6·1 answer
  • The scale on a map is 5 cm: 8 km.
    10·1 answer
  • Select the correct answer.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!