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Alla [95]
3 years ago
14

A certain committee consists of 17 people. From the committee, a president, a vice-president, and a treasurer are to be chosen.

In how many ways can these 3 offices be filled? Assume that a committee member can hold at most one of these offices.
Mathematics
1 answer:
Oksana_A [137]3 years ago
6 0
<h3>There are 4080 ways in which these 3 offices be filled.</h3>

Step-by-step explanation:

Here, the total number of candidates present in the committee  = 17

The posts for which people are to be elected are:

President, Vice -President and Treasurer  = 3 posts

Now, selecting a person for the post of president has total 17 ways.

⇒ The number of ways a president can be chosen = 17 ways

As, one person cannot hold 2 positions.

So, now the total candidates  = 17 - 1  = 16 people

⇒Selecting a person for the post of Vice -President has total 16 ways.

⇒ The number of ways a vice president can be chosen = 16 ways

Similarly, the number of ways a  Treasurer can be chosen = 15 ways

Combining the three ways, we get:

the number of ways President, Vice -President and Treasurer can be chosen   = 17 x 16 x 15  =  4080 ways

Hence, there are 4080 ways in which these 3 offices be filled.

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The percentage of people under the age of 18 was 23.5% in New York City, 25.8% in Chicago, and 26% in Los Angeles.
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0.0158 = 1.58% probability that all of them are under 18.

Step-by-step explanation:

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If three events, A, B and C are independent, the probability of all happening is the multiplication of the probabilities of each happening, that is:

P(A \cap B \cap C) = P(A)P(B)P(C)

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Find out more on linear equation at: brainly.com/question/13763238

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