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Vadim26 [7]
4 years ago
5

Solve for x in the equation shown below

Mathematics
1 answer:
baherus [9]4 years ago
3 0

Answer:

x = 14

Step-by-step explanation:

Step 1: First, Simplify the fraction.

\frac{4x}{7} =8

Step 2: Next, Multiply both sides by 7.

4x = 8 × 7

Step 3: Simplify 8 × 7 to 56.

4x = 56

Step 4: Then, Divide both sides by 4.

x=\frac{56}{7}

Step 5: Lastly, Simplify the fraction and you're done!

x = 14

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Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ
Ivan

Answer:

(-\infty,3)

Step-by-step explanation:

We are given that

(x-3)y''+4y=x

y''+\frac{4}{x-3}y=\frac{x}{x-3}

y(0)=0

y'(0)=1

By comparing with

y''+p(x)y'+q(x)y=g(x)

We get

p(x)=\frac{4}{x-3}

g(x)=\frac{x}{x-3}

q(x)=0

p(x),q(x) and g(x) are continuous for all real values of x except 3.

Interval on which p(x),q(x) and g(x) are continuous

(-\infty,3)and (3,\infty)

By unique existence theorem

Largest interval which contains 0=(-\infty,3)

Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution=(-\infty,3)

7 0
3 years ago
Find the measures of the numbered angles in the kite.
Dafna11 [192]

Answer:

1 is 90

2 is 52

Step-by-step explanation:

1 is a right angle so its 90

for 2 angles in a triangle equal to 180

so 180-90-38 is equal to 52

3 0
3 years ago
What statement is true? Use the number line to help
Scrat [10]

Answer:

-2 is greater than -2 1/2

Step-by-step explanation:

All the other questions are false and only answer a is correct because -2 is closer to 0 than -2 1/2.

7 0
3 years ago
Read 2 more answers
In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that
leonid [27]

Given:

Number of students who has a cat and a dog = 5

Number of students who has a cat but do not have a dog = 11

Number of students who has a dog but do not have a cat = 3

Number of students who neither have a cat nor a dog = 2

To find:

The probability that a student has a cat given that they do not have a dog.

Solution:

Let the following events:

A = Student has a cat

B = Do not have a dog

Total number of outcomes is:

5+3+11+2=21

The probability that a student has a cat but do not have a dog is:

P(A\cap B)=\dfrac{11}{21}

The probability that a student do not have a dog is:

P(B)=\dfrac{11+2}{21}

P(B)=\dfrac{13}{21}

The conditional probability is:

P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}

P\left(\dfrac{A}{B}\right)=\dfrac{\dfrac{11}{21}}{\dfrac{13}{21}}

P\left(\dfrac{A}{B}\right)=\dfrac{11}{13}

Therefore, the probability that a student has a cat given that they do not have a dog is \dfrac{11}{13}.

5 0
3 years ago
Type the ordered pair that is the solution to these equations.<br><br> 2x + 5y = -9<br> 3x - 4y = -2
victus00 [196]
The ordered pair that is the solution to these equations is (-2,-1)

work:

2(-2)+5(-1)=-9
3(-2)-4(-1)=-2
7 0
4 years ago
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